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# Q17: Meg and Bob are among the 5 participants in a cycling

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Manager
Joined: 11 Jan 2007
Posts: 197

Kudos [?]: 92 [0], given: 0

Location: Bangkok
Q17: Meg and Bob are among the 5 participants in a cycling [#permalink]

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03 Jun 2007, 20:40
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Q17:
Meg and Bob are among the 5 participants in a cycling race. If each participant finishes the race and no two participants finish at the same time, in how many different possible orders can the participants finish the race so that Meg finishes ahead of Bob?

A.24
B.30
C.60
D.90
E.120
_________________

cool

Kudos [?]: 92 [0], given: 0

CEO
Joined: 29 Mar 2007
Posts: 2554

Kudos [?]: 517 [0], given: 0

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03 Jun 2007, 22:30
5!/5!-3! = 5!/2! =60

C

Kudos [?]: 517 [0], given: 0

Manager
Joined: 14 Mar 2007
Posts: 235

Kudos [?]: 9 [0], given: 0

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04 Jun 2007, 05:14
1 2 3 4 5

meg B - - -
meg - B - -
meg - - B -
meg - - - B

4*1 +4*2 +4*3+4*4 +4*5=4+8+12+16+20=60

C is the one

Kudos [?]: 9 [0], given: 0

04 Jun 2007, 05:14
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