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Re: Quant Question of the Day Chat [#permalink]
Hlo

Where offical guide feature gone? In question bank forum
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Re: Quant Question of the Day Chat [#permalink]
Niv1992
Please solve without trigonometry
How can you solve without trigonometry? Even if we could operate the area ratio, (4cm²), they haven’t given enough data to consider them as similar triangles...
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Re: Quant Question of the Day Chat [#permalink]
You can find AD, DE, AE, EC.. without trigonometry.
Can anyone suggest how to find AB & BE?

By isosceles Right angle & 30-60-90 formula
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Re: Quant Question of the Day Chat [#permalink]
gmatophobia
PS Question 1 - August 04 30^20 - 20^20 is divisible by all of the following values, EXCEPT: A) 10 B) 25 C) 40 D) 60 E) 64 Source: GMATPrepNow | Difficulty: Hard
10^20 * (3-2)^20=10^20 is not divisible by 60. As 60 has 3 in it .
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Re: Quant Question of the Day Chat [#permalink]
AED = 90 SO EDC = 45 thus EDC =45
In triangle ABC, BCD = 30 . So in triangle DCE, angle DEC must be 90 , but is 15 . Wtf
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Re: Quant Question of the Day Chat [#permalink]
poojaarora1818
10^20 * (3-2)^20=10^20 is not divisible by 60. As 60 has 3 in it .
After simplification it comes out to be 10^20*(3^20-2^20).

Saurav444
AED = 90 SO EDC = 45 thus EDC =45 In triangle ABC, BCD = 30 . So in triangle DCE, angle DEC must be 90 , but is 15 . Wtf
Hi, its right angled at D hence ADE is 90 not AED is 90.
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Re: Quant Question of the Day Chat [#permalink]
gmatophobia
DS Question 1 - August 04 The average (arithmetic mean) of a list of positive numbers is what percent of the sum of the numbers? (1) The sum of the numbers in the list is 150. (2) There are 25 numbers in the list. Source: GMAT Club Tests | Difficulty: Medium

gmatophobia
PS Question 1 - August 04 30^20 - 20^20 is divisible by all of the following values, EXCEPT: A) 10 B) 25 C) 40 D) 60 E) 64 Source: GMATPrepNow | Difficulty: Hard

PS Question 1 - Aug 07

If k is the number of zeros at the end of n!, where n is a positive integer less than or equal to 100, then how many values can k take ?

A. 20
B. 21
C. 22
D. 24
E. 25

Source: GMAT Club Tests | Difficulty: Hard

DS Question 1 - Aug 07

Set S has six numbers and their average (arithmetic mean) is 32. What is the median of the numbers?

1) The six numbers are greater than or equal to 31
2) There is “37” in set S

Source: Math Revolution | Difficulty: Hard
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Re: Quant Question of the Day Chat [#permalink]
gmatophobia
DS Question 1 - Aug 07 Set S has six numbers and their average (arithmetic mean) is 32. What is the median of the numbers? 1) The six numbers are greater than or equal to 31 2) There is “37” in set S Source: Math Revolution | Difficulty: Hard
C

gmatophobia
PS Question 1 - Aug 07 If k is the number of zeros at the end of n!, where n is a positive integer less than or equal to 100, then how many values can k take ? A. 20 B. 21 C. 22 D. 24 E. 25 Source: GMAT Club Tests | Difficulty: Hard
Is the question framed properly? Because if n is 90 then the answer will be 21 but if is 100 then answer would be 24. I am unable to understand how to infer this question
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Re: Quant Question of the Day Chat [#permalink]
Sonia0106
Is the question framed properly? Because if n is 90 then the answer will be 21 but if is 100 then answer would be 24. I am unable to understand how to infer this question
I guess the question says that n=<100
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Re: Quant Question of the Day Chat [#permalink]
gmatophobia
PS Question 1 - Aug 07 If k is the number of zeros at the end of n!, where n is a positive integer less than or equal to 100, then how many values can k take ? A. 20 B. 21 C. 22 D. 24 E. 25 Source: GMAT Club Tests | Difficulty: Hard
I am not sure but IMO it’s A

gmatophobia
DS Question 1 - Aug 07 Set S has six numbers and their average (arithmetic mean) is 32. What is the median of the numbers? 1) The six numbers are greater than or equal to 31 2) There is “37” in set S Source: Math Revolution | Difficulty: Hard
IMO C
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Re: Quant Question of the Day Chat [#permalink]
gmatophobia
PS Question 1 - Aug 07 If k is the number of zeros at the end of n!, where n is a positive integer less than or equal to 100, then how many values can k take ? A. 20 B. 21 C. 22 D. 24 E. 25 Source: GMAT Club Tests | Difficulty: Hard
Number of Zeros at the end of factorial of any number ’n’ i.e. n! is given by: n/5 + n/5^2 + n/5^3 + ... and so on. Exponent of 5 is taken till we get non zero value of the division of individual terms. So here since n<=100, maximum number of trailing zeros = 100/5 + 100/25 + 100/125 +....

on solving it comes out to be 20 + 4 + 0 = 24. D is correct answer

this is applicable for any positive integer number ’n’
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Re: Quant Question of the Day Chat [#permalink]
gmatophobia
PS Question 1 - Aug 07 If k is the number of zeros at the end of n!, where n is a positive integer less than or equal to 100, then how many values can k take ? A. 20 B. 21 C. 22 D. 24 E. 25 Source: GMAT Club Tests | Difficulty: Hard
D - 24
Since n < = 100
Minimum 5 and 2 is required for a one 0 - 5x2 =10
So in 100!, 5 will repeat 24 times and 2 will repeat 97 time.

So answer is 24

gmatophobia
DS Question 1 - Aug 07 Set S has six numbers and their average (arithmetic mean) is 32. What is the median of the numbers? 1) The six numbers are greater than or equal to 31 2) There is “37” in set S Source: Math Revolution | Difficulty: Hard
C
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Re: Quant Question of the Day Chat [#permalink]
for-how-many-of-the-four-incentives-listed-does-each-of-the-companies-312370.html - anyone who would like to give this question a try?

Arpit_Bhardwaj
I guess the question says that n=<100
n<=100 means n can take any value between 1! to 100! and number of zeroes would vary accordingly
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Re: Quant Question of the Day Chat [#permalink]
Sonia0106
n<=100 means n can take any value between 1! to 100! and number of zeroes would vary accordingly
Yeah you are absolutely right and the question is asking us how many number of zeros are present in 100!.Just the way it is presented is a bit complex. If number of zeros can be 3 then it would mean eith k=1 or k=2 or k=3 and the question is asking us how many values can k take and the answer would be 3.
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Re: Quant Question of the Day Chat [#permalink]
Got it. Thanks Arpit
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Re: Quant Question of the Day Chat [#permalink]
Sonia0106
https://gmatclub.com/forum/for-how-many ... 12370.html - anyone who would like to give this question a try?
The question may sound exhausting, but if you have found what it is really asking , then it is very simple... it is asking for how many incentives of those four are always with a health insurance for any company. Basically, a company with a particular incentive should also have health insurance with it...how many such incentives are there?
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Re: Quant Question of the Day Chat [#permalink]
Yeah I got it but it was quite confusing at first.
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