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RiyazAhamed
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RiyazAhamed
“is it possible to assign each of the N students to one of the M classrooms so that each classroom has the same number of students” simply means is N divisible by M? That is, N/M? 1) given 3N is divisible by M Now, since M is between 3 and 13 and N is more than 13, this is not sufficient. Let’s say, M = 6, N = 60. 3N/M 3(60)/6 = Integer value. So, 60/6 = N/M = integer = yes possible to arrange each student to each class. However, if, M = 12 and N = 16. 3(16)/12 = 4 = integer value. But, N/M = 16/12 is not an integer. So, we may arrange or we may not arrange equally. Insufficient. B) given, 13N/M. We know 3<M<13<N. M has to be less than 13. That is M cannot be a multiple of 13 to cancel out that 13 in the numerator. Thus, N has to cancel out M in denominator to give us 13N/M as an integer. That is N/M is an integer. Thus, sufficient. Answer is B.
Thankyou so much. It cleared up all the confusion.
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Q. Is x=y ? 1) ax=ay 2) a^x=a^2y

Inequalities and Absolute Values
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Q. Is x=y ? 1) ax=ay 2) a^x=a^2y
1) ax-ay=0 a(x-y)=0.
Either x=y or a=0. INS
2) a can be 1 or 0 x or y can be anything or a is equal to 2 and y=1/2x
3) Since a can be 0 still, we cannot eliminate further

E
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A project is budgeted for 2400 hours and will last 3 weeks. Technicians will cover 25% of the project for the first week and then 60% for the final two weeks. If each technician normally works 40 hours per week, how many technicians are there?

A. 22
B. 12
C. 40
D. 32

Ayisa
A project is budgeted for 2400 hours and will last 3 weeks. Technicians will cover 25% of the project for the first week and then 60% for the final two weeks. If each technician normally works 40 hours per week, how many technicians are there? A. 22 B. 12 C. 40 D. 32
Can someone help me solve this?
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If we add up 25+60 that’s 85% ...is there something else in the question?
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A project is budgeted for 2400 hours and will last 3 weeks. Technicians will cover 25% of the project for the first week and then 60% for the final two weeks. If each technician normally works 40 hours per week, how many technicians are there?

There is no 42 in the options, thanks what is confusing me
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Are there any other options ?
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What I did as 600/40= 15 and then (.6*1800)/40 =27 then 27+14=42 ..
Don’t know what other might be bcz if I am substituting (40* any options) it is not fitting.
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Okay, thanks

$1,200,000
10. A project is budgeted for 1200 hours and will last 4 weeks. A labor covered 30% of the workload in the first two weeks and then covered 60% for the final two weeks. If a labor normally works 50 hours per week, how many total hours will the labor cover?

A. 220
B. 540
C. 360
D. 180
Can you try this one out?
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Ranu2024
What I did as 600/40= 15 and then (.6*1800)/40 =27 then 27+14=42 .. Don’t know what other might be bcz if I am substituting (40* any options) it is not fitting.
But same technicians could work in weeks 2 &3 as well?
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Ayisa
A project is budgeted for 2400 hours and will last 3 weeks. Technicians will cover 25% of the project for the first week and then 60% for the final two weeks. If each technician normally works 40 hours per week, how many technicians are there? A. 22 B. 12 C. 40 D. 32
Ans = 12
Each week 800h work has to be done
First week tech does 200h = 5 techs
2nd week tech does 480h = 12 techs
3rd week also 12

So we need atleast 12 techs
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Ayisa
A project is budgeted for 2400 hours and will last 3 weeks. Technicians will cover 25% of the project for the first week and then 60% for the final two weeks. If each technician normally works 40 hours per week, how many technicians are there?
2400 hours of work total.

1st week 25% of 2400 = 600 hours done.

Each worker works at the rate of 40 hours. So, 600/40 = 15 workers needed for first week.

2nd and 3rd week 60% of 2400 = 1440 hours done.

Each worker works at 40 hours per week, so for 2 weeks = 80 hours.

So, for 2nd and 3rd week, 1440/80 = 18 workers.

Total 15 + 18 = 33 workers are needed.

Is the answer 33?
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Ayisa
$1,200,000 10. A project is budgeted for 1200 hours and will last 4 weeks. A labor covered 30% of the workload in the first two weeks and then covered 60% for the final two weeks. If a labor normally works 50 hours per week, how many total hours will the labor cover? A. 220 B. 540 C. 360 D. 180 Can you try this one out?
30% * (300+300) + 60% *(300+300) = Answer is 540
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Hey can someone tell me from where I should practice IR ?

And what are the strategies to get 8+/12 in IR ?
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sh_076
30% * (300+300) + 60% *(300+300) = Answer is 540
Hi can you help as to why you did 300+300

sh_076
30% * (300+300) + 60% *(300+300) = Answer is 540
How did you come to the figure of 300+ 300
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muskanrajyan5
Hey can someone tell me from where I should practice IR ?
other than official questions?
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Ayisa
$1,200,000 10. A project is budgeted for 1200 hours and will last 4 weeks. A labor covered 30% of the workload in the first two weeks and then covered 60% for the final two weeks. If a labor normally works 50 hours per week, how many total hours will the labor cover? A. 220 B. 540 C. 360 D. 180 Can you try this one out?
The labor can only work for 200 hours max. So he will have worked for 90%*200 = 180 hours in total.

Option D.
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