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# Quant Question of the Day Chat

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Re: Quant Question of the Day Chat [#permalink]
Bunuel wrote:
This question is discussed here: x-y-z-are-po ... 76723.html

Thank Bunuel. However, the solution is not clear to me. It would be great if you could explain. Thanks in advance.
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Re: Quant Question of the Day Chat [#permalink]
My take on the above question:
For determining the denominator:
100 is to be divided in three non-zero positive variables and as it is positive, minimum value of all three is 1. Therefore, 97 is to be divided amongst three variables now. Place two separator between 97 identical elements and total therefore, total elements are now 99. Position of these seprator can be arranged in 99C2 ways.
For numerator we will have to use the condition x>20, y>10 and z>20. Therefore, taking their minimums as 21, 11 and 21 (totalling to 53), we are left with 47 to distribute among theee variables as earlier. This will give 49C2. So probability will be 49C2/99C2. @chetan2u @bunuel can verify if this makes sense or not

the-number-of-ordered-triplets-of-positive-integers-which-are-the-solu-355796.html

A similar question for basic understanding
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Re: Quant Question of the Day Chat [#permalink]
ria_kapoor wrote:
Hello Everyone . Can anyone please help with a detailed solution for this one?

treat this problem as a distribution of 100 chocolates between 3 students such that each will have atleast 1 chocolates
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Re: Quant Question of the Day Chat [#permalink]
We are to find the minimum sum of the blued boxes right?
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Re: Quant Question of the Day Chat [#permalink]
and for x> 20, y>10 and z>20 give them already 21,11, 21 respectively then problem will change into x + y + z = 47

PrabhatKC wrote:
We are to find the minimum sum of the blued boxes right?

15 ?

35 wanted A but in the end has 20 so 15 didn’t ended up in team A
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Re: Quant Question of the Day Chat [#permalink]
PrabhatKC wrote:
We are to find the minimum sum of the blued boxes right?

I think you maybe unable to reach to the solution because the table created by you is wrong. Horizontically it should be A, Not A and vertically it should be B, Not B. Try this you will reach to the solution. The solution for the same is discussed here : of-the-50-researchers-in-a-workgroup-40-percent-will-be-137538.html Hope it helps!
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Re: Quant Question of the Day Chat [#permalink]
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Re: Quant Question of the Day Chat [#permalink]
Someone help me with this question.
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Re: Quant Question of the Day Chat [#permalink]
rohinishivhare wrote:
Someone help me with this question.

Have you tried drawing the problem statement ? Drawing three circles with collinear centers while marking center-center distances might help.
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Re: Quant Question of the Day Chat [#permalink]
Actually I know the answer with normal difference method. But was trying in different way to reduce the time. But I was wrong
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Re: Quant Question of the Day Chat [#permalink]
rohinishivhare wrote:
Someone help me with this question.

is the answer 1.493 x 10^11??
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Re: Quant Question of the Day Chat [#permalink]
Purnank wrote:
1492.16 * 10^8

yes sorry my mistake
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Re: Quant Question of the Day Chat [#permalink]
If approximation works as pwr answer choice, you can take common factor as 3.84 and make 14.96 approximately 4 times of 3.84
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Re: Quant Question of the Day Chat [#permalink]
Aryaa03 wrote:
If approximation works as pwr answer choice, you can take common factor as 3.84 and make 14.96 approximately 4 times of 3.84

I find this method a little difficult, this is how I did it: 1.496 x10^11 is actually 1496 x 10^8 and distance till moon is also given in 10^8 terms. please correct me if I’m wrong
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Re: Quant Question of the Day Chat [#permalink]
I haven’t tried it on paper so far. You may be coreect if you have solved it already
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Re: Quant Question of the Day Chat [#permalink]
Purnank wrote:
12?

explain plz

rohinishivhare wrote:
9

no its 12
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Re: Quant Question of the Day Chat [#permalink]
Alex55 wrote:
explain plz

first for topmost 9 squares if you view from top view the squares which forms plus sign so out of those 5 remove center piece you will get 4 pieces will have 2 face black. Then the 2 vertical corner cubes of each side of first two layers, total we have 4 sides, So, 4*2 = 8 such cubes Therefore total of 8+4 = 12 cubes
Re: Quant Question of the Day Chat [#permalink]
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