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Quant Question of the Day Chat

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Re: Quant Question of the Day Chat [#permalink]
 Problem Solving Butler: July 2024 July 4 PS 1 PS 2
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Re: Quant Question of the Day Chat [#permalink]
Yes I solved through this method
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Re: Quant Question of the Day Chat [#permalink]
Register for the BIGGEST GMAT competition of the year:­

\$30,000 Prizes at GMAT Club Olympics July 8 -19, 2024­
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Re: Quant Question of the Day Chat [#permalink]
If the population of a certain country increases at the rate of one person every 15 seconds, by how many persons does the population have in 20 minutes? (Initial population= 5)

Is this the way?
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Re: Quant Question of the Day Chat [#permalink]
It will be 80+5=85 if initial population is 5

4 persons in 1 minute so 80 persons in 20 mins
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Re: Quant Question of the Day Chat [#permalink]
Yes 85 will be correct ans
Acc. To me also !

it is very easy qn
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Re: Quant Question of the Day Chat [#permalink]
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Re: Quant Question of the Day Chat [#permalink]
Excuse me, but this is a question I made from that easy question. I’d like to know, how to find the total number of population there is at the end of 20 minute. Re read the question again
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Re: Quant Question of the Day Chat [#permalink]
 Data Sufficiency Butler: July 2024 July 5 DS 1 DS 2
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Re: Quant Question of the Day Chat [#permalink]
 Problem Solving Butler: July 2024 July 5 PS 1 PS 2
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Re: Quant Question of the Day Chat [#permalink]
K is a three digit number such that the ratio of the number to the sum of its digits is least. What is the difference between the hundreds and the tens digits of K
a) 9
b) 8
c) 7
d) None of these
I was able to solve this question by using hit and trial but could not think of a proper way to solve it.
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Re: Quant Question of the Day Chat [#permalink]
We want to minimise 100a+10b+c/a+b+c
This is equal to
1+99a+9b/a+b+c
and this is clearly least when c is greatest. So we have c=9
.

We then rewrite the fraction as
100−90b+99c/a+b+c
which is least when a
is least. So we have a=1
.

Isolating b
as above gives
10+90a−9ca+b+c
Since a
is non-zero the numerator is positive and the minimum is obtained when b=9
.
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Re: Quant Question of the Day Chat [#permalink]
how to refresh my account for get rank
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GMAT 1: 760 Q56 V59
Re: Quant Question of the Day Chat [#permalink]
a-large-cube-consists-of-216-small-identical-cubes-what-is-the-number-400287.html

A large cube consists of 216 small identical cubes. What is the number of small cubes that do not have a face that is part of a face of the large cube?

A. 54

B. 58

C. 64

D. 76

E. 86

Cube root of 216- 6
Number of cube inside= (N-2)^3= (6-2)^3= 64

i am not getting the solution anyone help plz
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Re: Quant Question of the Day Chat [#permalink]
Since the large cube is made up of 216 small cubes, its side length is equal to the cubed root of 216, which is 6. Therefore, each layer has 6 x 6 = 36 small cubes, and the total number of small cubes on the inside is 36 x 4 = 144. Therefore, 144 of the smaller cubes have no faces painted at all.
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Re: Quant Question of the Day Chat [#permalink]
ሉባባዪመር wrote:
We want to minimise 100a+10b+c/a+b+c
This is equal to
1+99a+9b/a+b+c
and this is clearly least when c is greatest. So we have c=9
.

We then rewrite the fraction as
100−90b+99c/a+b+c
which is least when a
is least. So we have a=1
.

Isolating b
as above gives
10+90a−9ca+b+c
Since a
is non-zero the numerator is positive and the minimum is obtained when b=9
.

But for same if we rewrite the fraction in 100 - 90b+c/a+b+c
Here I can see a must be max.

That’s why I have a doubt !

99c*

this way of solving is bit confusing
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Re: Quant Question of the Day Chat [#permalink]
Five chairs surround a big round table in a class. Each of 5 students, A, B, C, D and E sit on one of the chairs. A must sit opposite from the white board and B must sit next to A. How many seating arrangements are there?

A. 12
B. 24
C. 4
D. 48
E. 60

Can anyone tell the simplest way of solution..

Is it 60 or 12 could someone please explain..
Re: Quant Question of the Day Chat [#permalink]
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