Quant Question of the Day Chat

I still would stick to what I said, Yes they mentioned “all C machines can ONLY install on filled cans” but stem never said the viceversa that “all the filled cans are to/must be installed”.

I’m waiting for OE to check how to justify case 1 statement.

"DS Question 1 - Dec 23" is an official question and the OE is C

Thanks, can your provide link for official explanation?

Hello there! I am an aspiring enhancing around quant which full over me over the time to solve these tricky question which now have been a hobby for me so could you please share me dec 22 all questions of quant

PS Question 1 - Dec 24

m and n are positive integers. What is the smallest possible value of integer m if m/n = 0.3636363636...?

A. 3
B. 4
C. 7
D. 13
E. 22

Source: GMAT Club Tests | Difficulty: Medium

DS Question 1 - Dec 24

Company M has two divisions - X and Y. Each division has exactly two types of employees - clerks and managers. Is the ratio of clerks to managers greater for division X than that for division Y?

(1) Division X has 20% managers.
(2) Company M has 15% managers.

Source: Expert’s Global | Difficulty: Medium

DS Question 2 - Dec 24

Is x < y < z ?

(1) |x-1| < y < z+1

(2) |x+1| < y < z-1

Source: Math Revolution | Difficulty: Hard

aah ! I guess you’re missing something

PS Question 2 - Dec 24

Set A: {x, x, x, y, y, y, 3x+y, x–y }

If the median of set A is 10 and 0 < x < y, what is the range of set A?

A. 10
B. 20
C. 30
D. 40
E. 60

Source: Magoosh | Difficulty: Medium

Can you please expulsin ?

St.1 is quite straight forward and its not sufficient.

St.2
y and (z -1 ) are positive number as both lie to the right of |x+1| (modulus is always non negative).

Also, as y < z - 1, we can conclude that z lies right on the number line compared to y.

So, the relative position of y and z on the number line is

----- y ----- z ------

|x + 1| is less than y.

Therefore we can infer that the distance between x and -1 is less than the value of y.

Regardless of which side of -1 ’x’ lies, the value of ’x’ will always be less than the value of y.

We can visualize this by plotting x , y and -1 on the number line.

----- -1 ----- x ----- y ------

----- x ----- -1 ----- y ------

Hence we can conclude that x < y < z

Option B

DS Question 1 - Dec 25

If x and y are positive integers, what is the greatest common divisor of x and y?

(1) 2x + y = 73
(2) 5x – 3y = 1

Source: Manhattan GMAT | Difficulty: Hard

PS Question 1 - Dec 25

At a local beach, the ratio of little dogs to average dogs to enormous dogs is 2:5:8. Late in the afternoon, the ratio of little dogs to average dogs doubles and the ratio of little dogs to enormous dogs increases. If the new percentage of little dogs and the new percentage of average dogs are both integers and there are fewer than 30 total dogs at the beach, which of the following represents a possible new percentage of enormous dogs?

A. 25%
B. 40%
C. 50%
D. 55%
E. 70%

Source: Veritas Prep | Difficulty: Hard

Can someone explain me how to solve this problem 😥

There js probably a discussion but you would do the following

(x+y)^2-(x-y)^2

expand it to
x^2+2xy+y^2-(x^2-2xy+y^2)
Simplify into 4xY
So really its 2^4xy
xy=1, so 2^4 which is just 16

PS Question 1 - Dec 26

Find the number of trailing zeros in (23!+24!+26!).

A. 2
B. 4
C. 5
D. 8
E. 10

Source: Others | Difficulty: Hard

DS Question 1 - Dec 26

If a, b, and c are integers and a < b < c, are a, b, and c consecutive integers?

(1) The median of {a!, b!, c!} is an odd number.

(2) c! is a prime number.

Source: GMAT Club Tests | Difficulty: Hard

Only factorial who has odd value is 0! or 1! b=0 or 1, but this is clearly not sufficient.

2) c! is prime - only 2! is prime.

3) There are no negative factorials, so b cannot =0. Therefore, a=0 b=1 c=3

Suff

Answer would be B or C?