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gmatophobia
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Why do you think its E ? From Statement 1, we can conclude that N is an integer as N is a sum of two integers. 16A = 3N The LHS is an even number, hence, N has to be even. Do you see any issue with this reasoning ?
yeah... missed this part. Both statements together are sufficient
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DS Question 1 - Feb 17 If A and B are integers, is N an even integer? (1) 11A + 4B = N (2) 5A – 4B = 2N Source: GMATPrepNow | Difficulty: Medium

gmatophobia
PS Question 1 - Feb 17 If the circus were to sell all of its 220 tickets for this month’s performance at its usual price, the revenue from sales would be 10% greater than that collected last month. If the circus raised the ticket price by 5% and sold only 200 tickets as a result, what percent less would last month’s revenue be compared to this month’s revenue? A. 2 B. 5 C. 100/21 D. 110/20 E. 9/4 Source: GMAT Club Tests | Difficulty: Hard

DS Question 1- Feb 19

Is x+y > 0

(1) x - y = 1

(2) x/y < 1

Source: Expert’s Global | Difficulty: Medium

PS Question 1- Feb 19

A deck of cards contains 6 cards numbered from 1, 2, 3, 4, 5, and to 6. If three cards are randomly selected one by one from the deck without replacement, what is the probability that the numbers on the cards are in increasing order?

A. 1/60
B. 1/30
C. 1/20
D. 1/6
E. 1/3

Source: GMAT Club Tests | Difficulty: Medium
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gmatophobia
PS Question 1- Feb 19 A deck of cards contains 6 cards numbered from 1, 2, 3, 4, 5, and to 6. If three cards are randomly selected one by one from the deck without replacement, what is the probability that the numbers on the cards are in increasing order? A. 1/60 B. 1/30 C. 1/20 D. 1/6 E. 1/3 Source: GMAT Club Tests | Difficulty: Medium
6 ways/ 6 x 5 x 4 total ways =1/20
Answer C
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6 ways/ 6 x 5 x 4 total ways =1/20 Answer C
Sorry I stand corrected 20 ways / 6 x 5 x 4 total ways =1/6 choiceD is the answer

The20 ways are 123,124,125,126,134,135,136,145,146, 156, 234,235,236, 245,246,256,345,346,356 ,456
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gmatophobia
PS Question 1- Feb 19 A deck of cards contains 6 cards numbered from 1, 2, 3, 4, 5, and to 6. If three cards are randomly selected one by one from the deck without replacement, what is the probability that the numbers on the cards are in increasing order? A. 1/60 B. 1/30 C. 1/20 D. 1/6 E. 1/3 Source: GMAT Club Tests | Difficulty: Medium

gmatophobia
DS Question 1- Feb 19 Is x+y > 0 (1) x - y = 1 (2) x/y < 1 Source: Expert’s Global | Difficulty: Medium

PS Question 1- Feb 21

The set of solutions for the equation (x^2–25)^2=x^2–10x+25 contains how many real numbers?

A. 0
B. 1
C. 2
D. 3
E. 4

Source: Official Guide | Difficulty: Hard

DS Question 1- Feb 21

If a, b, and c are three-digit positive integers and if a = b + c, is the hundreds digit of a greater than the sum of the hundreds digits of b and c ?

(1) The tens digit of a is equal to the sum of the tens digits of b and c.
(2) The tens digit of a is equal to the product of the tens digits of b and c.

Source: GMAT Club Test | Difficulty: Hard
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gmatophobia
PS Question 1- Feb 21 The set of solutions for the equation (x^2–25)^2=x^2–10x+25 contains how many real numbers? A. 0 B. 1 C. 2 D. 3 E. 4 Source: Official Guide | Difficulty: Hard
option D. three real solutions : -6, -4 , 5

gmatophobia
DS Question 1- Feb 21 If a, b, and c are three-digit positive integers and if a = b + c, is the hundreds digit of a greater than the sum of the hundreds digits of b and c ? (1) The tens digit of a is equal to the sum of the tens digits of b and c. (2) The tens digit of a is equal to the product of the tens digits of b and c. Source: GMAT Club Test | Difficulty: Hard
Option D. both statements are saying that nothing is carried over to hundred’s place while adding the tens place. so the sum of hundreds digit of "b" and "c" is equal to that of "a"
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gmatophobia
DS Question 1- Feb 21 If a, b, and c are three-digit positive integers and if a = b + c, is the hundreds digit of a greater than the sum of the hundreds digits of b and c ? (1) The tens digit of a is equal to the sum of the tens digits of b and c. (2) The tens digit of a is equal to the product of the tens digits of b and c. Source: GMAT Club Test | Difficulty: Hard
Option E

gmatophobia
PS Question 1- Feb 21 The set of solutions for the equation (x^2–25)^2=x^2–10x+25 contains how many real numbers? A. 0 B. 1 C. 2 D. 3 E. 4 Source: Official Guide | Difficulty: Hard
Is this Option D
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Working alone at its constant rate, machine K took 3 hours to produce 1/4 of the units produced last Friday. Then machine M started working and the two machines, working simultaneously at their respective constant rates, took 6 hours to produce the rest of the units produced last Friday. How many hours would it have taken machine M, working alone at its constant rate, to produce all of the units produced last Friday?

A. 8
B. 12
C. 16
D. 24
E. 30

What will be LCM here? How to solve this using lcm method
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The question is very easy if you solve by logic than by the LCM method.

Machine K produces 1/4 units in 3 hours, so to produce 4 times the units (i.e. to produce 1 unit) the machine will take 12 hours

Given: When 1/4 of the work was done, machine M joins in and together they complete the production in 6 hours

So together M and K complete 3/4 of production in 6 hours

Hence, they will complete 1 unit of production in 4/3 times the time taken = 4/3 * 6 = 8 hours

Time taken together = Time taken by M1 * Time taken by M2 / Time taken by M1 + M2

8 = 12*M / 12 + M

Solve for M

M = 24

Few more questions on similar logic

Question Posted by Bunuel

oven-a-takes-5-hrs-longer-than-oven-b-to-bake-y-pizzas-406910.html

Official Question

running-at-their-respective-constant-rates-machine-x-takes-2-days-98599.html
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Shivam29
How is this D
Which question are you referring to ?
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gmatophobia
PS Question 1- Feb 21 The set of solutions for the equation (x^2–25)^2=x^2–10x+25 contains how many real numbers? A. 0 B. 1 C. 2 D. 3 E. 4 Source: Official Guide | Difficulty: Hard

gmatophobia
DS Question 1- Feb 21 If a, b, and c are three-digit positive integers and if a = b + c, is the hundreds digit of a greater than the sum of the hundreds digits of b and c ? (1) The tens digit of a is equal to the sum of the tens digits of b and c. (2) The tens digit of a is equal to the product of the tens digits of b and c. Source: GMAT Club Test | Difficulty: Hard

DS Question 1 - Feb 23

What is the sum of 3 consecutive integers?

(1) The sum of the 3 integers is less than the greatest of the 3 integers.
(2) Of the 3 integers, the ratio of the least to the greatest is 3.

Source: Official Guide | Difficulty : Medium

PS Question 1 - Feb 23

If integer C is randomly selected from 20 to 99, inclusive. What is the probability that C^3 - C is divisible by 12 ?

A. 1/2
B. 2/3
C. 3/4
D. 4/5
E. 1/3

Source: Manhattan | Difficulty : Hard
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gmatophobia
DS Question 1 - Feb 23 What is the sum of 3 consecutive integers? (1) The sum of the 3 integers is less than the greatest of the 3 integers. (2) Of the 3 integers, the ratio of the least to the greatest is 3. Source: Official Guide | Difficulty : Medium
option B: as -1, -2, -3 are the three consecutive integers
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option B: as -1, -2, -3 are the three consecutive integers
more concrete analysis of B:
let the first digit be x, the third digit would be x+2
As we have a ratio, x cannot be 0.
Therefore, (x+2)/x=3
Solving for x, you get that x is 1.

A small error:
X must be greater than 0, because otherwise the ratio would be 1/3 not 3/1 (-1 would be the largest, -3 would be smallest)

A is easily out because it works for any pair of negative integers. So therefore, B must be the correct answer
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PS Question 1 - Feb 23 If integer C is randomly selected from 20 to 99, inclusive. What is the probability that C^3 - C is divisible by 12 ? A. 1/2 B. 2/3 C. 3/4 D. 4/5 E. 1/3 Source: Manhattan | Difficulty : Hard
What about this question
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Shivam29
What about this question
I am outside rn and cant solve iy wjth my head

but: For a number to be divisible by 12, it needs to be divisible by 4 and 3

c^3-c is 3 consecutive integers - so there will be always 1 multiple of 3. Now you just need to find the values of C that are multiples of 2
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gmatophobia
PS Question 1 - Feb 23 If integer C is randomly selected from 20 to 99, inclusive. What is the probability that C^3 - C is divisible by 12 ? A. 1/2 B. 2/3 C. 3/4 D. 4/5 E. 1/3 Source: Manhattan | Difficulty : Hard
Option C. Detailed analysis of option C:

c^3-c can be simplified as product of 3 consecutive int
product of 3 number is divisible by 3
now, question reduces to check whether (c-1)c(c+1) is div by 4

we can have (even*odd*even) as product to satisfy this, as product of 2 even integer will be divisible with 4: there are 40 numbers like this.
AND we can have (odd*even*odd) as product provided that even number in the middle is div by 4: we have 20 cases like this.


so, probablilty = (40+20)/80 = 3/4
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DS Question 1 - Feb 23 What is the sum of 3 consecutive integers? (1) The sum of the 3 integers is less than the greatest of the 3 integers. (2) Of the 3 integers, the ratio of the least to the greatest is 3. Source: Official Guide | Difficulty : Medium

gmatophobia
PS Question 1 - Feb 23 If integer C is randomly selected from 20 to 99, inclusive. What is the probability that C^3 - C is divisible by 12 ? A. 1/2 B. 2/3 C. 3/4 D. 4/5 E. 1/3 Source: Manhattan | Difficulty : Hard
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