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# Queens and Diamond

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Manager
Joined: 29 May 2008
Posts: 111

Kudos [?]: 127 [0], given: 0

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16 Jun 2009, 05:25
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What is the probability of drawing a queen or a diamond from a normal shuffled deck?

a) 2/3
b) 4/13
c) 17/52
d) 16/51
e) 1/4

Kudos [?]: 127 [0], given: 0

Current Student
Joined: 13 May 2008
Posts: 141

Kudos [?]: 25 [1], given: 6

Schools: LBS

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16 Jun 2009, 06:05
1
KUDOS
b) 4/13...

there are 4 Queens and 13 diamonds IN A 52 deck card.. so:

P(queen or diamond) = P(queen) + P(diamond) − P(queen and diamond)
P(queen or diamond) = (4/52) + (13/52) − (1/52)
P(queen or diamond) = 16/52
P(queen or diamond) = 4/13..

hope that helps you understand it!

Kudos [?]: 25 [1], given: 6

Manager
Joined: 29 May 2008
Posts: 111

Kudos [?]: 127 [0], given: 0

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16 Jun 2009, 07:18
Absolutely now I got it

Kudos [?]: 127 [0], given: 0

Current Student
Joined: 13 May 2008
Posts: 141

Kudos [?]: 25 [1], given: 6

Schools: LBS

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16 Jun 2009, 07:39
1
KUDOS
i don't get no kudos!!!

Kudos [?]: 25 [1], given: 6

Manager
Joined: 16 Apr 2009
Posts: 230

Kudos [?]: 102 [0], given: 10

Schools: Ross

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19 Jun 2009, 20:27
One kudo for MJ2009...
Your post helped me a lot...
_________________

Keep trying no matter how hard it seems, it will get easier.

Kudos [?]: 102 [0], given: 10

Manager
Joined: 07 Jun 2009
Posts: 204

Kudos [?]: 46 [0], given: 9

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19 Jun 2009, 21:37
MJ2009 wrote:
b) 4/13...

there are 4 Queens and 13 diamonds IN A 52 deck card.. so:

P(queen or diamond) = P(queen) + P(diamond) − P(queen and diamond)
P(queen or diamond) = (4/52) + (13/52) − (1/52)
P(queen or diamond) = 16/52
P(queen or diamond) = 4/13..

hope that helps you understand it!

Good explanation
_________________

Kudos [?]: 46 [0], given: 9

Director
Joined: 04 Jan 2008
Posts: 893

Kudos [?]: 790 [0], given: 17

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19 Jun 2009, 22:15
Simply awesome
more because of the datailing part
+1 from me as well

MJ2009 wrote:
b) 4/13...

there are 4 Queens and 13 diamonds IN A 52 deck card.. so:

P(queen or diamond) = P(queen) + P(diamond) − P(queen and diamond)
P(queen or diamond) = (4/52) + (13/52) − (1/52)
P(queen or diamond) = 16/52
P(queen or diamond) = 4/13..

hope that helps you understand it!

_________________

http://gmatclub.com/forum/math-polygons-87336.html
http://gmatclub.com/forum/competition-for-the-best-gmat-error-log-template-86232.html

Kudos [?]: 790 [0], given: 17

Re: Queens and Diamond   [#permalink] 19 Jun 2009, 22:15
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