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Author Message
Joined: 31 Dec 1969
Location: Russian Federation
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WE: Supply Chain Management (Energy and Utilities)
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05 Jun 2004, 13:11
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

please explain how to do this. thanks

F(n)=1/n â€“ 1/(n+1) what is the sum of the first 100 integers?
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05 Jun 2004, 20:55
f(1) + F(2) = 1- 1/2 + 1/2 -1/3
= 1 - 1/3
= 2/3

similarly
f(1) + F(2) + F (3)

= 1- 1/3 + 1/3 -1/4
= 1 - 1/4
= 3/ 4

so sum up to = n/(n+1)

there fore sum upto 100

= 100/101
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Praveen

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08 May 2005, 23:14
praveen_rao7 wrote:
= 100/101

i think praveen did a good job.

sum of the first 100 integers = f1+f2+f3+f4+f5+.........+f100
= 1/1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+1/5-1/6.........+1/100-1/101.
=1/1-1/101=(101-1)/101=100/101
08 May 2005, 23:14
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