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# Question from Challenge 6

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CEO
Joined: 15 Aug 2003
Posts: 3452

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Question from Challenge 6 [#permalink]

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22 Feb 2006, 07:37
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Thanks for answering the last question. Here one of three questions i am posting today. Please explain your answer choice.

What is the least possible value of x?

(1) x^2 - 5x + 5 = 1 - x
(2) x^2 = 4
(A) Statement (1) ALONE is sufficient, but Statement (2) alone is not sufficient.
(B) Statement (2) ALONE is sufficient, but Statement (1) alone is not sufficient.
(C) BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
(D) EACH statement ALONE is sufficient.
(E) Statements (1) and (2) TOGETHER are NOT sufficient.

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Director
Joined: 17 Dec 2005
Posts: 544

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Location: Germany

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22 Feb 2006, 08:53
(1) x^2 - 5x + 5 = 1 - x

(x-2)^2=0

x=2 v x=-2

(2) x^2 = 4
x=2 v x=-2

both statements lead to x=-2 as the least possible value of x

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Director
Joined: 24 Oct 2005
Posts: 572

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Location: NYC

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22 Feb 2006, 16:07
I believe D..
It is asking for least possible value.. and least possible value can be -2
_________________

Success is my only option, failure is not -- Eminem

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Manager
Joined: 15 Aug 2005
Posts: 132

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22 Feb 2006, 17:18
Agree with D.

What is the least possible value of x?

(1) x^2 - 5x + 5 = 1 - x
(2) x^2 = 4

i] x^2 - 5x + 5 = 1 - x
=> (x-2)^2=0
so x=2 ----suff

ii] x^2 = 4
=> (x-2)(x+2)=0
so x=-2,2 since -2 is smaller it is the least value here - suff

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Manager
Joined: 20 Mar 2005
Posts: 201

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Location: Colombia, South America

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22 Feb 2006, 17:32
good question, is not really testing math but how much you understand the tricks of the GMAT, I'll go with D as well

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Senior Manager
Joined: 05 Jan 2006
Posts: 381

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22 Feb 2006, 20:25
1) (x-2)^2 = 0 => x= +- 2
2) x^2=4 =>x= +- 2

both are sufficient so answer is D

Chirag

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Manager
Joined: 20 Feb 2006
Posts: 213

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22 Feb 2006, 20:39
Guys,
I too agree with D.
But, the least possible value from statement(1) is 2 (and not +/-2).
(x-2)^2 = 0 => x = 2 only.

Kudos [?]: 21 [0], given: 0

22 Feb 2006, 20:39
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# Question from Challenge 6

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