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# R = 1 + 2xy + x^2y^2; what is value of xy? 1.) R = 0 2.)

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Director
Joined: 11 Sep 2006
Posts: 515

Kudos [?]: 40 [0], given: 0

R = 1 + 2xy + x^2y^2; what is value of xy? 1.) R = 0 2.) [#permalink]

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14 Oct 2006, 12:53
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

R = 1 + 2xy + x^2y^2; what is value of xy?

1.) R = 0
2.) x>0
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Kudos [?]: 40 [0], given: 0

Manager
Joined: 01 Oct 2006
Posts: 240

Kudos [?]: 14 [0], given: 0

Re: Powerprep question [#permalink]

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14 Oct 2006, 13:12
uphillclimb wrote:
R = 1 + 2xy + x^2y^2; what is value of xy?

1.) R = 0
2.) x>0

I think 1 is sufficient

1 + 2xy + x^2y^2 = 0
(xy)^2 + 2(xy) +1 = 0
(xy + 1)^2 = 0

xy = -1.

2 is insufficient and irrelevant

Kudos [?]: 14 [0], given: 0

SVP
Joined: 01 May 2006
Posts: 1794

Kudos [?]: 170 [0], given: 0

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14 Oct 2006, 13:31
Agree with (A) as explained by mst

Kudos [?]: 170 [0], given: 0

14 Oct 2006, 13:31
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# R = 1 + 2xy + x^2y^2; what is value of xy? 1.) R = 0 2.)

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