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# R^c)(R^d)(R^e) = R^-12 if R>0, and c, d, e are each

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Joined: 04 Jun 2007
Posts: 366
R^c)(R^d)(R^e) = R^-12 if R>0, and c, d, e are each [#permalink]

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12 Aug 2007, 11:51
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(R^c)(R^d)(R^e) = R^-12
if R>0, and c, d, e are each different negative integers, what is the smallest that c could be?
A) -12
B) -10
C) -9
D) -6
E) -1

here is what I thought-
R^c+d+e = R^-12
c+d+e = -12
if we choose c= -1, d= -9 and e= -2
-1-9-2 = -12
so the smallest c could be is -1, but that's not the OA, I understand why kaplan has a different answer than me coz it does make sense, but I dont understand why my solution cannot be correct? Any help is appreciated.
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Joined: 03 May 2007
Posts: 872
Schools: University of Chicago, Wharton School

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12 Aug 2007, 11:59
r019h wrote:
(R^c)(R^d)(R^e) = R^-12
if R>0, and c, d, e are each different negative integers, what is the smallest that c could be?
A) -12
B) -10
C) -9
D) -6
E) -1

here is what I thought-
R^c+d+e = R^-12
c+d+e = -12
if we choose c= -1, d= -9 and e= -2
-1-9-2 = -12
so the smallest c could be is -1, but that's not the OA, I understand why kaplan has a different answer than me coz it does make sense, but I dont understand why my solution cannot be correct? Any help is appreciated.

C. you are almost there. it is -9 not -1.

-9 is smaller than -1.
Re: kaplan 800 PS   [#permalink] 12 Aug 2007, 11:59
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