Check GMAT Club Decision Tracker for the Latest School Decision Releases https://gmatclub.com/AppTrack

 It is currently 24 May 2017, 19:33

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# R is a set containing 8 different numbers. S is a set

Author Message
TAGS:

### Hide Tags

Director
Status: Finally Done. Admitted in Kellogg for 2015 intake
Joined: 25 Jun 2011
Posts: 537
Location: United Kingdom
GMAT 1: 730 Q49 V45
GPA: 2.9
WE: Information Technology (Consulting)
Followers: 77

Kudos [?]: 3378 [0], given: 217

R is a set containing 8 different numbers. S is a set [#permalink]

### Show Tags

25 Feb 2012, 05:06
4
This post was
BOOKMARKED
00:00

Difficulty:

45% (medium)

Question Stats:

53% (02:02) correct 47% (01:06) wrong based on 208 sessions

### HideShow timer Statistics

R is a set containing 8 different numbers. S is a set containing 7 different numbers, all of which are members of R. Which of the following statements CANNOT be true?

(A) The range of R is less than the range of S.
(B) The mean of R is greater than the mean of S.
(C) The range of R is equal to the range of S.
(D) The mean of R is less than the mean of S.
(E) The mean of R is equal to the mean of S.

I got he right answer (
[Reveal] Spoiler:
A
) but had to some guess work on choice D. Any idea how can we prove that choice
[Reveal] Spoiler:
D
can be true as well?
[Reveal] Spoiler: OA

_________________

Best Regards,
E.

MGMAT 1 --> 530
MGMAT 2--> 640
MGMAT 3 ---> 610
GMAT ==> 730

Math Expert
Joined: 02 Sep 2009
Posts: 38858
Followers: 7728

Kudos [?]: 106056 [1] , given: 11607

### Show Tags

25 Feb 2012, 05:39
1
KUDOS
Expert's post
1
This post was
BOOKMARKED
enigma123 wrote:
R is a set containing 8 different numbers. S is a set containing 7 different numbers, all of which are members of R. Which of the following statements CANNOT be true?

(A) The range of R is less than the range of S.
(B) The mean of R is greater than the mean of S.
(C) The range of R is equal to the range of S.
(D) The mean of R is less than the mean of S.
(E) The mean of R is equal to the mean of S.

I got he right answer (A) but had to some guess work on choice D. Any idea how can we prove that choice D can be true as well?

The range of a set is the difference between the largest and smallest elements of a set.

So, the answer is straight A: the range of a subset cannot be more than the range of a whole set: how can the difference between the largest and smallest elements of a subset be more than the difference between the largest and smallest elements of a whole set.

As for D:
Consider set R to be {-3, -2, -1, 0, 1, 2, 3, 4} --> mean=0.5.

(D) The mean of R is less than the mean of S --> remove the smallest term -3, then the mean of S will be 1, so more than 0.5.

Hope it's clear.
_________________
Intern
Joined: 05 Mar 2014
Posts: 25
Followers: 0

Kudos [?]: 26 [0], given: 20

Re: R is a set containing 8 different numbers. S is a set [#permalink]

### Show Tags

07 May 2014, 04:59
HI Bunuel, consider this Set R = { 1,2,3,4,5,6,7,8} and set S = {1,2,3,5,6,7,8}, in this case, the range for both set R and set S is 7.

Kindly let me know if am missing something here ?

Thanks
Math Expert
Joined: 02 Sep 2009
Posts: 38858
Followers: 7728

Kudos [?]: 106056 [0], given: 11607

Re: R is a set containing 8 different numbers. S is a set [#permalink]

### Show Tags

07 May 2014, 05:34
virinchiwiwo wrote:
HI Bunuel, consider this Set R = { 1,2,3,4,5,6,7,8} and set S = {1,2,3,5,6,7,8}, in this case, the range for both set R and set S is 7.

Kindly let me know if am missing something here ?

Thanks

Yes, the ranges are equal but what's your question?
_________________
Intern
Joined: 22 Jun 2013
Posts: 42
Followers: 0

Kudos [?]: 45 [0], given: 132

### Show Tags

09 May 2014, 01:15
Bunuel wrote:
enigma123 wrote:
R is a set containing 8 different numbers. S is a set containing 7 different numbers, all of which are members of R. Which of the following statements CANNOT be true?

(A) The range of R is less than the range of S.
(B) The mean of R is greater than the mean of S.
(C) The range of R is equal to the range of S.
(D) The mean of R is less than the mean of S.
(E) The mean of R is equal to the mean of S.

I got he right answer (A) but had to some guess work on choice D. Any idea how can we prove that choice D can be true as well?

The range of a set is the difference between the largest and smallest elements of a set.

So, the answer is straight A: the range of a subset cannot be more than the range of a whole set: how can the difference between the largest and smallest elements of a subset be more than the difference between the largest and smallest elements of a whole set.

As for D:
Consider set R to be {-3, -2, -1, 0, 1, 2, 3, 4} --> mean=0.5.

(D) The mean of R is less than the mean of S --> remove the smallest term -3, then the mean of S will be 1, so more than 0.5.

Hope it's clear.

Hello Bunuel

Sorry ! I am not able to imagine the case where the Mean of the subset will be same as the Mean of its Super Set. i.e. Option E
Please provide an example for that

Thanks a lot for your help !
Intern
Joined: 31 Jan 2016
Posts: 27
Schools: Rotman '19 (A)
Followers: 0

Kudos [?]: 1 [0], given: 6

Re: R is a set containing 8 different numbers. S is a set [#permalink]

### Show Tags

06 Oct 2016, 19:09
niyantg wrote:
Bunuel wrote:
enigma123 wrote:
R is a set containing 8 different numbers. S is a set containing 7 different numbers, all of which are members of R. Which of the following statements CANNOT be true?

(A) The range of R is less than the range of S.
(B) The mean of R is greater than the mean of S.
(C) The range of R is equal to the range of S.
(D) The mean of R is less than the mean of S.
(E) The mean of R is equal to the mean of S.

I got he right answer (A) but had to some guess work on choice D. Any idea how can we prove that choice D can be true as well?

The range of a set is the difference between the largest and smallest elements of a set.

So, the answer is straight A: the range of a subset cannot be more than the range of a whole set: how can the difference between the largest and smallest elements of a subset be more than the difference between the largest and smallest elements of a whole set.

As for D:
Consider set R to be {-3, -2, -1, 0, 1, 2, 3, 4} --> mean=0.5.

(D) The mean of R is less than the mean of S --> remove the smallest term -3, then the mean of S will be 1, so more than 0.5.

Hope it's clear.

Hello Bunuel

Sorry ! I am not able to imagine the case where the Mean of the subset will be same as the Mean of its Super Set. i.e. Option E
Please provide an example for that

Thanks a lot for your help !

Can someone explain answer choice E?

I think there is an error in this question?
Re: R is a set containing 8 different numbers. S is a set   [#permalink] 06 Oct 2016, 19:09
Similar topics Replies Last post
Similar
Topics:
1 A set of data contains 5 different numbers whose average is 8.8. After 2 20 May 2017, 07:19
5 S is a set containing 8 different positive odd numbers 3 11 Dec 2015, 02:03
16 A is a set containing 7 different numbers. B is a set contai 6 29 Feb 2016, 01:13
24 S is a set containing 9 different numbers. T is a set contai 12 17 Apr 2017, 22:32
6 S is a set containing 9 different numbers. T is a set contai 4 18 Jan 2014, 03:47
Display posts from previous: Sort by