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# R is a set containing 8 different numbers. S is a set

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Status: Finally Done. Admitted in Kellogg for 2015 intake
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GMAT 1: 730 Q49 V45
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R is a set containing 8 different numbers. S is a set [#permalink]

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25 Feb 2012, 05:06
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Difficulty:

45% (medium)

Question Stats:

55% (01:00) correct 45% (01:05) wrong based on 223 sessions

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R is a set containing 8 different numbers. S is a set containing 7 different numbers, all of which are members of R. Which of the following statements CANNOT be true?

(A) The range of R is less than the range of S.
(B) The mean of R is greater than the mean of S.
(C) The range of R is equal to the range of S.
(D) The mean of R is less than the mean of S.
(E) The mean of R is equal to the mean of S.

I got he right answer (
[Reveal] Spoiler:
A
) but had to some guess work on choice D. Any idea how can we prove that choice
[Reveal] Spoiler:
D
can be true as well?
[Reveal] Spoiler: OA

_________________

Best Regards,
E.

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25 Feb 2012, 05:39
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enigma123 wrote:
R is a set containing 8 different numbers. S is a set containing 7 different numbers, all of which are members of R. Which of the following statements CANNOT be true?

(A) The range of R is less than the range of S.
(B) The mean of R is greater than the mean of S.
(C) The range of R is equal to the range of S.
(D) The mean of R is less than the mean of S.
(E) The mean of R is equal to the mean of S.

I got he right answer (A) but had to some guess work on choice D. Any idea how can we prove that choice D can be true as well?

The range of a set is the difference between the largest and smallest elements of a set.

So, the answer is straight A: the range of a subset cannot be more than the range of a whole set: how can the difference between the largest and smallest elements of a subset be more than the difference between the largest and smallest elements of a whole set.

As for D:
Consider set R to be {-3, -2, -1, 0, 1, 2, 3, 4} --> mean=0.5.

(D) The mean of R is less than the mean of S --> remove the smallest term -3, then the mean of S will be 1, so more than 0.5.

Hope it's clear.
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Re: R is a set containing 8 different numbers. S is a set [#permalink]

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07 May 2014, 04:59
HI Bunuel, consider this Set R = { 1,2,3,4,5,6,7,8} and set S = {1,2,3,5,6,7,8}, in this case, the range for both set R and set S is 7.

Kindly let me know if am missing something here ?

Thanks

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Re: R is a set containing 8 different numbers. S is a set [#permalink]

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07 May 2014, 05:34
virinchiwiwo wrote:
HI Bunuel, consider this Set R = { 1,2,3,4,5,6,7,8} and set S = {1,2,3,5,6,7,8}, in this case, the range for both set R and set S is 7.

Kindly let me know if am missing something here ?

Thanks

Yes, the ranges are equal but what's your question?
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09 May 2014, 01:15
Bunuel wrote:
enigma123 wrote:
R is a set containing 8 different numbers. S is a set containing 7 different numbers, all of which are members of R. Which of the following statements CANNOT be true?

(A) The range of R is less than the range of S.
(B) The mean of R is greater than the mean of S.
(C) The range of R is equal to the range of S.
(D) The mean of R is less than the mean of S.
(E) The mean of R is equal to the mean of S.

I got he right answer (A) but had to some guess work on choice D. Any idea how can we prove that choice D can be true as well?

The range of a set is the difference between the largest and smallest elements of a set.

So, the answer is straight A: the range of a subset cannot be more than the range of a whole set: how can the difference between the largest and smallest elements of a subset be more than the difference between the largest and smallest elements of a whole set.

As for D:
Consider set R to be {-3, -2, -1, 0, 1, 2, 3, 4} --> mean=0.5.

(D) The mean of R is less than the mean of S --> remove the smallest term -3, then the mean of S will be 1, so more than 0.5.

Hope it's clear.

Hello Bunuel

Sorry ! I am not able to imagine the case where the Mean of the subset will be same as the Mean of its Super Set. i.e. Option E
Please provide an example for that

Thanks a lot for your help !

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Re: R is a set containing 8 different numbers. S is a set [#permalink]

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06 Oct 2016, 19:09
niyantg wrote:
Bunuel wrote:
enigma123 wrote:
R is a set containing 8 different numbers. S is a set containing 7 different numbers, all of which are members of R. Which of the following statements CANNOT be true?

(A) The range of R is less than the range of S.
(B) The mean of R is greater than the mean of S.
(C) The range of R is equal to the range of S.
(D) The mean of R is less than the mean of S.
(E) The mean of R is equal to the mean of S.

I got he right answer (A) but had to some guess work on choice D. Any idea how can we prove that choice D can be true as well?

The range of a set is the difference between the largest and smallest elements of a set.

So, the answer is straight A: the range of a subset cannot be more than the range of a whole set: how can the difference between the largest and smallest elements of a subset be more than the difference between the largest and smallest elements of a whole set.

As for D:
Consider set R to be {-3, -2, -1, 0, 1, 2, 3, 4} --> mean=0.5.

(D) The mean of R is less than the mean of S --> remove the smallest term -3, then the mean of S will be 1, so more than 0.5.

Hope it's clear.

Hello Bunuel

Sorry ! I am not able to imagine the case where the Mean of the subset will be same as the Mean of its Super Set. i.e. Option E
Please provide an example for that

Thanks a lot for your help !

Can someone explain answer choice E?

I think there is an error in this question?

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Re: R is a set containing 8 different numbers. S is a set   [#permalink] 06 Oct 2016, 19:09
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