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Raffle tickets numbered consecutively from 101 through 350 [#permalink]
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30 Jul 2012, 02:05
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The Official Guide for GMAT® Review, 13th Edition  Quantitative Questions ProjectRaffle tickets numbered consecutively from 101 through 350 are placed in a box. What is the probability that a ticket selected at random will have a number with a hundreds digit of 2 ? (A) 2/5 (B) 2/7 (C) 33/83 (D) 99/250 (E) 100/249 Practice Questions Question: 10 Page: 153 Difficulty: 600 GMAT Club is introducing a new project: The Official Guide for GMAT® Review, 13th Edition  Quantitative Questions ProjectEach week we'll be posting several questions from The Official Guide for GMAT® Review, 13th Edition and then after couple of days we'll provide Official Answer (OA) to them along with a slution. We'll be glad if you participate in development of this project: 1. Please provide your solutions to the questions; 2. Please vote for the best solutions by pressing Kudos button; 3. Please vote for the questions themselves by pressing Kudos button; 4. Please share your views on difficulty level of the questions, so that we have most precise evaluation. Thank you!
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Re: Raffle tickets numbered consecutively from 101 through 350 [#permalink]
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Re: Raffle tickets numbered consecutively from 101 through 350 [#permalink]
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30 Jul 2012, 02:47
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numbers with hundreds digit 2 are 200299 100 such numbers
total numbers are 101350 250 such numbers
probability would be \(\frac{100}{250}\) \(\frac{2}{5}\)



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Re: Raffle tickets numbered consecutively from 101 through 350 [#permalink]
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03 Aug 2012, 05:05



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Re: Raffle tickets numbered consecutively from 101 through 350 [#permalink]
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07 Apr 2014, 19:44
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Re: Raffle tickets numbered consecutively from 101 through 350 [#permalink]
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15 Mar 2015, 08:45
Bunuel, why do we think that the question means 'inclusive' 101 and 350?
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Re: Raffle tickets numbered consecutively from 101 through 350 [#permalink]
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Re: Raffle tickets numbered consecutively from 101 through 350 [#permalink]
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15 Mar 2015, 08:53
Then if it didn't mean inclusive, how else it could present the problem? Could you answer, pls?
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Re: Raffle tickets numbered consecutively from 101 through 350 [#permalink]
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Re: Raffle tickets numbered consecutively from 101 through 350 [#permalink]
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15 Mar 2015, 09:00
Thank you very much Bunuel for your help.
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Re: Raffle tickets numbered consecutively from 101 through 350 [#permalink]
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Bunuel wrote: The Official Guide for GMAT® Review, 13th Edition  Quantitative Questions ProjectRaffle tickets numbered consecutively from 101 through 350 are placed in a box. What is the probability that a ticket selected at random will have a number with a hundreds digit of 2 ? (A) 2/5 (B) 2/7 (C) 33/83 (D) 99/250 (E) 100/249 Practice Questions Question: 10 Page: 153 Difficulty: 600 GMAT Club is introducing a new project: The Official Guide for GMAT® Review, 13th Edition  Quantitative Questions ProjectEach week we'll be posting several questions from The Official Guide for GMAT® Review, 13th Edition and then after couple of days we'll provide Official Answer (OA) to them along with a slution. We'll be glad if you participate in development of this project: 1. Please provide your solutions to the questions; 2. Please vote for the best solutions by pressing Kudos button; 3. Please vote for the questions themselves by pressing Kudos button; 4. Please share your views on difficulty level of the questions, so that we have most precise evaluation. Thank you! Total numbers = 350 101 +1 = 250 favorable cases = 299200 +1 = 100 Probability = 100/250 = 2/5 option A.
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Re: Raffle tickets numbered consecutively from 101 through 350 [#permalink]
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10 Apr 2016, 05:21
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Re: Raffle tickets numbered consecutively from 101 through 350 [#permalink]
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03 May 2016, 11:29
Bunuel wrote: The Official Guide for GMAT® Review, 13th Edition  Quantitative Questions ProjectRaffle tickets numbered consecutively from 101 through 350 are placed in a box. What is the probability that a ticket selected at random will have a number with a hundreds digit of 2 ? (A) 2/5 (B) 2/7 (C) 33/83 (D) 99/250 (E) 100/249 The probability of an event is equal to: favorable outcomes/total outcomes In this particular problem we have: favorable outcomes = numbers with a hundreds digit of 2 total outcomes = consecutive integers from 101 through 350 Let’s start with the total outcomes. Although the word “inclusive” is not actually used, it is implied because we are told the raffle tickets start at 101 and end at 350. Thus, the number of tickets from 101 to 350, inclusive, is 350 – 101 + 1 = 250. (Note that we had to add 1 because we counted BOTH tickets 101 and 350.) The favorable outcomes are the number of tickets with a hundreds digit of 2. Since all the numbers from 200 to 299 are included, there are 299 – 200 +1 = 100 numbers with a hundreds digit of 2. Therefore, the probability that a randomly selected ticket with have a hundreds digit of 2 is 100/250 = 2/5. Answer A.
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Re: Raffle tickets numbered consecutively from 101 through 350 [#permalink]
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19 Nov 2016, 15:56
Wow got this wrong... I somehow missed 200 in the set and marked D




Re: Raffle tickets numbered consecutively from 101 through 350
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