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Rahim bought 100 kg potato from market & 99% of its are water so he dr
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07 Dec 2019, 18:06
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GMATBusters’ Quant Quiz Question 4 Rahim bought 100 kg potato from market & 99% of its are water so he dried it whole night to make it 98% water. In the morning How many kilogram of potato left to him? A) 25 B) 40 C) 50 D) 65 E) 80
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Re: Rahim bought 100 kg potato from market & 99% of its are water so he dr
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07 Dec 2019, 19:15
Answer:C
Assuming the overnight drying did not reduce the mass. (Mass remains constant)
@ 99% water content Mass=1% =1 *100kg/100=1Kg
After drying
@98% water content
Mass =2%
this should be equal to 1kg as Mass should remain constant.
(Final potato wt left )* 2/100=1 Final potato wt left=100/2=50



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Re: Rahim bought 100 kg potato from market & 99% of its are water so he dr
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07 Dec 2019, 20:06
Rahim bought 100 kg potato from market & 99% of its are water so he dried it whole night to make it 98% water. In the morning How many kilogram of potato left to him?
100 kg  potato > 99 kg water and 1 kg potato peel.
when he dried it whole night, the rate of water was changed, not the potato peel. > Well, before the rate of potato peel was 1%. After drying it, the rate of potato peel was changed to 2%.
1 kg 2 % x  100 > \(x= \frac{100}{2}= 50 kg\) In the morning, he got 50 kg potato.
The answer is C.



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Re: Rahim bought 100 kg potato from market & 99% of its are water so he dr
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07 Dec 2019, 23:58
Ans:C 100kg=99kg water+ 1kg potato solid After drying Xkg=98% of X water + 2% of X potato solid Since, Potato solid will be constant hence, 2/100*X=1kg X=50Kg.



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Re: Rahim bought 100 kg potato from market & 99% of its are water so he dr
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08 Dec 2019, 00:22
100kgs of potato has 99% water ; or say 99kgs water and 1 kgs of other weight ; later the water 99 % becomes 98 % and other 2% is 1 part ; 1/2 100*1/2 ; 50 kgs IMO C
Rahim bought 100 kg potato from market & 99% of its are water so he dried it whole night to make it 98% water. In the morning How many kilogram of potato left to him? A) 25 B) 40 C) 50 D) 65 E) 80



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Re: Rahim bought 100 kg potato from market & 99% of its are water so he dr
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08 Dec 2019, 01:33
It is given that 100 kg potato from market & 99% of its are water Potato starch=1kg water = 99kg
Rahim dried it whole night to make it 98% water. We know that some of the water will be evaporated while drying in the sun. Let the water left after drying=x kg
x/(x+1) * 100 = 98 100x= 98x+98 2x=98 x=49
we already have 1 kg of potato starch, so total weight=49+1=50 kg C is the answer



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Re: Rahim bought 100 kg potato from market & 99% of its are water so he dr
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08 Dec 2019, 02:31
100kg 99% water 1% mass so 1% of 100= 1kg
after evaporation 98%water left, as mass remains constant now >> 1kg=2% of 100 kg 1=2/100 =50kg



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Re: Rahim bought 100 kg potato from market & 99% of its are water so he dr
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08 Dec 2019, 03:03
Rahim bought 100 kg potato from market & 99% of its are water so he dried it whole night to make it 98% water. In the morning How many kilogram of potato left to him? A) 25 B) 40 C) 50 D) 65 E) 80
Initially, we have 99 Kg of water in 100 Kg of potato and 1 Kg of potato by weight. Let w = the amount of water that evaporates, and we can create the equation: (99  w)/(100  w) = 98/100 100(99  w) = 98(100  w) 9900  100w = 9800  98w 100 = 2w 50 = w As 50 Kg of water evaporated, new weight of the potatoes will be 100  50 = 50 Kg.
Imo. C



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Re: Rahim bought 100 kg potato from market & 99% of its are water so he dr
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08 Dec 2019, 04:37
100 gms contains 99 gms water & 1 gms of potato
After evaporation of water let X be the weight of potato
The potato is now 2%, hence, we have 1 = (2/100)* X
Hence Answer is Option C
Solving we get, X = 50 gms



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Re: Rahim bought 100 kg potato from market & 99% of its are water so he dr
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08 Dec 2019, 04:43
as per qs, 100 Kg of Potato contains 99 kg of water & 1 kg of potato (at start).
After a night drying, potato % = 2%. let P be new weight of potato (after drying).
potato's new weight is 2% of total weight, which is equal to 1 kg = (2/100)* P
Solving we get, P = 50 Kgs
Answer should be C.



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Re: Rahim bought 100 kg potato from market & 99% of its are water so he dr
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08 Dec 2019, 05:11
The answer is C: 50
EXPLANATION:
Let's assume x kg of water was dried from the 100kg of potatoes. Earlier, it was 99% water. Now, it becomes 98% water. So, our equation becomes:
\( (99x)/(100x) = 98/100 \)
The above equation signifies that x kg of water is removed from 99% water (and subsequently 100% of potatoes), giving 98% of water.
Solving the above equation, we get x = 50.
Now, the potato left would be the one after water is dried, which is 100  x = 100  50 = 50 kg.
Hence, 50 kg is the answer.



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Re: Rahim bought 100 kg potato from market & 99% of its are water so he dr
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08 Dec 2019, 05:32
100 kg potatoes are available. Initially, 99% water and 1% potato pulp is present. 99% water = 99 kg water 1% potato pulp = 1 kg potato pulp.
Finally, 98% water and 2% potato pulp is present.
Since there is no change in the potato pulp quantity, Therefore initial quantity of pulp = final quantity of pulp Or, 2% potato pulp = 1 kg potato pulp Or, 100% potato pulp = 50 kg potato pulp. Therefore, he is left with 50 kg of potatoes.



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Re: Rahim bought 100 kg potato from market & 99% of its are water so he dr
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09 Dec 2019, 04:29
100 kg potatoes are there.
Initially, 99% water + 1% potato mash = 100% potatoes. ⇒ 99 kg water + 1 kg potato mash = 100 kg potatoes
Finally, 98% water + 2% potato mash = 100% potatoes
But, there is no change in the potato pulp quantity.
So, initial quantity of potato mash = final quantity of potato mash ⇒ 2% potato mash = 1 kg potato mash ⇒ 100% potato mash = 50 kg potato mash. Therefore, 50 kg of potatoes are left with him.
C is the answer.



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Re: Rahim bought 100 kg potato from market & 99% of its are water so he dr
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09 Dec 2019, 05:08
100kg potatoes will have 99kg water & 1kg potatoes
When Rahim dried the potatoes, only the water quantity was reduced by evaporation but the original quantity of potatoes stayed the same.
Let x be the amount of water evaporated. From 99kg water, if x kg is evaporated, the remaining amount of water will be (99x)kg. Also, the total weight is reduced by x i.e. (100x)
(99x)/(100x) = 98/100
The above equation says the remaining amount of water, upon the remaining amount of the original quantity is 98%
Solving it we get x = 50.
Since the amount evaporated is 50kg, the remaining weight is 50kg of which 49kg is water and 1kg is potatoes.
Kindly note that this could easily be a trick question on GMAT. Coincidentally x=50 and the final answer is also 100x = 50. If the original quantity was something different, say 120, and the equations solved to give x=50, the amount remaining would be 10050=70. In the haste, a lot of people would mark 50. Remember to check the question being asked and answer that question.



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Re: Rahim bought 100 kg potato from market & 99% of its are water so he dr
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12 Dec 2019, 07:45
gmatbusters wrote: GMATBusters’ Quant Quiz Question 4 Rahim bought 100 kg potato from market & 99% of its are water so he dried it whole night to make it 98% water. In the morning How many kilogram of potato left to him? A) 25 B) 40 C) 50 D) 65 E) 80 100 kg = potato + water 100 kg = 99 potato + 1 water 0.98(100x)=99x x=50 Ans (C)



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Re: Rahim bought 100 kg potato from market & 99% of its are water so he dr
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29 Mar 2020, 05:15
P W Tot Before 1 99 100 (99%water in 100Kg potato, then xKg water is evaporated) After 2 98 100x ( new total is 100x and 98% water so 2Kg is new potato content )
Since P ie potato solid content remains the same ie P1/(P1+W1)= 1/1+99= P2/(P2+W2) 1/100 * 100= 2/100 * (100x) 100=2002x so x=50 ; now potato content left = 10050=50Kg




Re: Rahim bought 100 kg potato from market & 99% of its are water so he dr
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