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Bill spends two days driving from Point A to Point B.
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24 Oct 2016, 08:50

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Bill spends two days driving from Point A to Point B . On the first day, he drove 2 hours longer and at an average speed 5 miles per hour faster than he drove on the second day. If during the two days he drove a total of 680 miles over the course of 18 hours, what was his average speed on the second day, in miles per hour?

A) 20 B) 25 C) 28 D) 30 E) 35

Hi does anyone have an easier way to try solve this?

Re: Bill spends two days driving from Point A to Point B.
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24 Oct 2016, 09:09

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grantcke wrote:

Bill spends two days driving from Point A to Point B . On the first day, he drove 2 hours longer and at an average speed 5 miles per hour faster than he drove on the second day. If during the two days he drove a total of 680 miles over the course of 18 hours, what was his average speed on the second day, in miles per hour?

A) 20 B) 25 C) 28 D) 30 E) 35

First recognize that we have TWO pieces of information regarding the time Bill spent driving each day. On day 1, Bill drove 2 hours longer than he drove on day 2. So, let x = # of driving hours on day 2 Then x + 2 = # of driving hours on day 1

Bill drove a TOTAL of 18 hours So, x + (x + 2) = 18 Simplify: 2x + 2 = 18 Solve, x = 8 So, Bill drove 10 hours on day 1 and he drove 8 hours on day 2

Now let's solve the question by starting with a word equation. Let x = speed driven on day 2 So, x + 5 = speed driven on day 1

(Distance traveled on day 1) + (Distance traveled on day 2) = 680 Distance = (rate)(time) We get: (x+ 5)(10) + (x)(8) = 680 Expand: 10x + 50 + 8x = 680 Simplify: 18x + 50 = 680 18x = 630 x = 35 (mph)

Re: Bill spends two days driving from Point A to Point B.
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25 Oct 2016, 07:56

grantcke wrote:

Bill spends two days driving from Point A to Point B . On the first day, he drove 2 hours longer and at an average speed 5 miles per hour faster than he drove on the second day. If during the two days he drove a total of 680 miles over the course of 18 hours, what was his average speed on the second day, in miles per hour?

A) 20 B) 25 C) 28 D) 30 E) 35

Hi does anyone have an easier way to try solve this?

Forma table -

Attachment:

TABLE.PNG [ 3.6 KiB | Viewed 2593 times ]

2T + 2 = 18

So, 2T = 16

Or, t = 8

Attachment:

Table 2.PNG [ 3.76 KiB | Viewed 2591 times ]

Now, 10s + 50 + 8s = 680

Or, 18s = 630

Or, s = 35 Hence, average speed on day 2 was 35, answer will be (E)... _________________

Thanks and Regards

Abhishek....

PLEASE FOLLOW THE RULES FOR POSTING IN QA AND VA FORUM AND USE SEARCH FUNCTION BEFORE POSTING NEW QUESTIONS

Re: Bill spends two days driving from Point A to Point B.
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13 Dec 2017, 16:26

grantcke wrote:

Bill spends two days driving from Point A to Point B . On the first day, he drove 2 hours longer and at an average speed 5 miles per hour faster than he drove on the second day. If during the two days he drove a total of 680 miles over the course of 18 hours, what was his average speed on the second day, in miles per hour?

A) 20 B) 25 C) 28 D) 30 E) 35

We are given that on the first day, Bill drove 2 hours longer and at an average speed 5 miles per hour faster than he drove on the second day. We can let the rate on the second day = r and the rate on the first day = r + 5. Also, we can let the time on the second day = t and the time on the first day = t + 2.

Since the total time is 18, we can create the following equation to determine t:

t + t + 2 = 18

2t = 16

t = 8

Thus, the distance on day 2 is 8r and the distance on day 1 is (r + 5)(10) = 10r + 50

We can create the following equation to determine r:

8r + 10r + 50 = 680

18r = 630

r = 35

Answer: E
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