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Three grades of milk are 1 percent, 2 percent, and 3 percent by volume. If x gallons of the 1 percent grade, y gallons of the 2 percent grade, and z gallons of the 3 percent are mixed to give x+y+z gallons of the 1.5 percent grade, what is x in terms of y and z?

A)y+3z B) y+z/4 c)2y + 3z d)3y+z e)3y+4.5z

x + 2y + 3z = 1.5(x + y + z) 0.5x = 0,5y + 1,5z x = y + 3z

Thanks for the replies. I think I am confused with the setup. Originally, I thought this was a weighted average problem and setup (x + 2y + 3z) / 6 = 1.5 which would be the equation for weighted average. Obviously, this is wrong but I think conceptually I am missing something. Why couldn't I have done the weighted average way?

x+ 2y + 3z = 1.5(x + y + z) note: we can divide by 100 on both sides to indicate the % amount, but since it would be common to both sides hence the equation will take the above form. 0.5x = 0.5y + 1.5z x = y + 3z Hence 'A'
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Three grades of milk are 1%, 2%, and 3% fat by volume. If x gallons of the 1% grade, y gallons of the 2% grade, and z gallons of the 3% grade are mixed to give x+y+z gallons a 1.5% grade, what is x in terms of y and z?

A)y+3z B)(y+z)/4 C)2y+3z D)3y+z E)3y+4.5z

x+2y+3z = 1.5(x+y+z)

0.5x= 0.5y + 1.5z

x = y+3z. Answer A.
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Confused as to solving this.please need some input. thx

Three grades of milk are 1 percent, 2 percent, 3 percent fat by volume. if x gallons of the 1 percent grade, y gallons of the 2 percent grade, and z gallons of the 3 percent grade are mixed to give x+y+z gallons of a 1.5 percent grade, what is x in terms of y and z.

a) y + 3z b) (y+z)/4 c) 2y + 3z d) 3y + z e) 3y + 4.5z