GMAT Question of the Day - Daily to your Mailbox; hard ones only

It is currently 17 Oct 2019, 08:24

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel

Rectangle ABCD has AB = 3 and BC = 4. Point E is the foot of the perpe

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:

Hide Tags

Find Similar Topics 
Math Expert
User avatar
V
Joined: 02 Sep 2009
Posts: 58401
Rectangle ABCD has AB = 3 and BC = 4. Point E is the foot of the perpe  [#permalink]

Show Tags

New post 13 May 2019, 01:03
00:00
A
B
C
D
E

Difficulty:

  85% (hard)

Question Stats:

43% (02:46) correct 58% (02:58) wrong based on 40 sessions

HideShow timer Statistics

Director
Director
avatar
D
Joined: 19 Oct 2018
Posts: 970
Location: India
Premium Member CAT Tests
Re: Rectangle ABCD has AB = 3 and BC = 4. Point E is the foot of the perpe  [#permalink]

Show Tags

New post 14 May 2019, 03:55
1
BE=3*4/5=2.4
EC= BC^2/AC
AC^2=3^2+4^2
AC=5
EC= 4^2/5=3.2

Perpendicular distance of E from BC= 2.4*3.2/4= 1.92
Perpendicular distance of E from AD=3-1.92=1.08

Area of AED= 0.5*1.08*4=2.16 or 54/25

Bunuel wrote:
________________________
BUMPING FOR DISCUSSION.
Director
Director
avatar
D
Joined: 19 Oct 2018
Posts: 970
Location: India
Premium Member CAT Tests
Rectangle ABCD has AB = 3 and BC = 4. Point E is the foot of the perpe  [#permalink]

Show Tags

New post Updated on: 17 Jul 2019, 12:37
1
Area of triangle ABC= 1/2*AB*BC=1/2*AC*BE
\(BE= \frac{AB*BC}{AC}\)=\(\frac{4*3}{5}\)=2.4


stne wrote:
nick1816 wrote:
BE=3*4/5=2.4
EC= BC^2/AC
AC^2=3^2+4^2
AC=5
EC= 4^2/5=3.2

Perpendicular distance of E from BC= 2.4*3.2/4= 1.92
Perpendicular distance of E from AD=3-1.92=1.08

Area of AED= 0.5*1.08*4=2.16 or 54/25

Bunuel wrote:
________________________
BUMPING FOR DISCUSSION.



Hi nick1816,
A little elaboration could help. How did you calculate BE?

Attachments

y.png
y.png [ 8.22 KiB | Viewed 492 times ]


Originally posted by nick1816 on 16 Jul 2019, 13:08.
Last edited by nick1816 on 17 Jul 2019, 12:37, edited 1 time in total.
Senior Manager
Senior Manager
avatar
G
Joined: 25 Jul 2018
Posts: 266
Re: Rectangle ABCD has AB = 3 and BC = 4. Point E is the foot of the perpe  [#permalink]

Show Tags

New post 16 Jul 2019, 13:38
1
Please find the attached file

Posted from my mobile device
Attachments

File comment: PFA
C72E6766-7B43-48A8-BE91-FD9A745D1660.jpeg
C72E6766-7B43-48A8-BE91-FD9A745D1660.jpeg [ 2.13 MiB | Viewed 487 times ]

Director
Director
User avatar
V
Joined: 27 May 2012
Posts: 901
Re: Rectangle ABCD has AB = 3 and BC = 4. Point E is the foot of the perpe  [#permalink]

Show Tags

New post 16 Jul 2019, 12:41
nick1816 wrote:
BE=3*4/5=2.4
EC= BC^2/AC
AC^2=3^2+4^2
AC=5
EC= 4^2/5=3.2

Perpendicular distance of E from BC= 2.4*3.2/4= 1.92
Perpendicular distance of E from AD=3-1.92=1.08

Area of AED= 0.5*1.08*4=2.16 or 54/25

Bunuel wrote:
________________________
BUMPING FOR DISCUSSION.



Hi nick1816,
A little elaboration could help. How did you calculate BE?
_________________
- Stne
Director
Director
User avatar
V
Joined: 27 May 2012
Posts: 901
Re: Rectangle ABCD has AB = 3 and BC = 4. Point E is the foot of the perpe  [#permalink]

Show Tags

New post 17 Jul 2019, 12:34
nick1816 wrote:
Area of triangle ABC= 1/2*AB*BC=1/2*AC*BE
\(BE= \frac{AB*AC}{AC}\)=\(\frac{4*3}{5}\)=2.4


stne wrote:
nick1816 wrote:
BE=3*4/5=2.4
EC= BC^2/AC
AC^2=3^2+4^2
AC=5
EC= 4^2/5=3.2

Perpendicular distance of E from BC= 2.4*3.2/4= 1.92
Perpendicular distance of E from AD=3-1.92=1.08

Area of AED= 0.5*1.08*4=2.16 or 54/25




Hi nick1816,
A little elaboration could help. How did you calculate BE?


Hi nick1816,

Thanks man, but there is a small typo above , it should be BE=\(\frac{AB*BC}{AC}\), Hope you'll correct it. Thanks.
_________________
- Stne
GMAT Club Bot
Re: Rectangle ABCD has AB = 3 and BC = 4. Point E is the foot of the perpe   [#permalink] 17 Jul 2019, 12:34
Display posts from previous: Sort by

Rectangle ABCD has AB = 3 and BC = 4. Point E is the foot of the perpe

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  





Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne