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# Rectangle ABCD with a perimeter of 60 is inscribed in a circle with a

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Intern
Joined: 11 May 2014
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Location: United States
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Rectangle ABCD with a perimeter of 60 is inscribed in a circle with a [#permalink]

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11 Jun 2014, 16:01
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Rectangle ABCD with a perimeter of 60 is inscribed in a circle with a radius of $$7.5\sqrt{2}$$. What is the area of ABCD?

A. 150
B. 225
C. 450
D. 750
E. 900
[Reveal] Spoiler: OA

Last edited by Bunuel on 27 Mar 2017, 13:00, edited 2 times in total.
Renamed the topic and edited the question.
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Re: Rectangle ABCD with a perimeter of 60 is inscribed in a circle with a [#permalink]

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12 Jun 2014, 01:18
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tinku21rahu wrote:
Rectangle ABCD with a perimeter of 60 is inscribed in a circle with a radius of 7.5$$\sqrt{2}$$. What is the area of ABCD?
A) 150
B) 225
C) 450
D) 750
E) 900

let length be 'l' and breadth be 'b'

2(l+b)=60; l+b=30
also; 2r = diagonal of the rectangle ABCD, thus diagonal = 15\sqrt{2}

also we know that if l and b are length and breadth then length of diagonal = \sqrt{l^2 +b^2} =15\sqrt{2}
squaring both sides we have, l^2+b^2=450

area of the rectangle = lb

also, we know that $$(l+b)^2$$ = $$l^2$$ + $$b^2$$ +2lb;

substituting l+b=30; l^2+b^2 = 450 in the above equation we have;

900=450+2lb;
450=2lb;
or lb=225
hence area =225
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Re: Rectangle ABCD with a perimeter of 60 is inscribed in a circle with a [#permalink]

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13 Jun 2014, 20:48
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Refer diagram below:

Perimeter = 60

If one side = x, then

other side would be = 30 - x

Diameter of circle = Diagonal of rectangle

$$= 2* 7.5\sqrt{2}$$

$$= 15\sqrt{2}$$

Setting up the equation

$$(15\sqrt{2})^2 = x^2 + (30-x)^2$$

$$x^2 - 30x + 225 = 0$$

$$(x - 15)^2 = 0$$

x = 15

Area = 15 * 15 = 225 (This rectangle is a square)

Bunuel, Kindly update the OA

One more thing,

I understand that every square is a rectangle & every rectangle NEED NOT have to be a square. However, in this question, they mentioned rectangle ABCD which turns up to be a square. Is the wording correct for this question?

Thanks
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Rectangle ABCD with a perimeter of 60 is inscribed in a circle with a [#permalink]

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12 Nov 2017, 09:36
Guys, first post here...
Bunuel PareshGmat

Just checking if my workaround would be correct.
Since the radius = 7.5\sqrt{2}, it's correct to say that the 4 inner triangles are isosceles and that their angles are 45:45:90.

Following the rule for 45:45:90 triangles, the largest side would be 1:\sqrt{2}, leaving us with 7.5\sqrt{2} * \sqrt{2} = 7.5 * 2 = 15 (for all triangles).

With this information we can calculate the area of ABCD (which turns out to be a square) as 15 * 15 = 225.
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Rectangle ABCD with a perimeter of 60 is inscribed in a circle with a [#permalink]

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14 Nov 2017, 02:02
tinku21rahu wrote:
Attachment:
Geo.png
Rectangle ABCD with a perimeter of 60 is inscribed in a circle with a radius of $$7.5\sqrt{2}$$. What is the area of ABCD?

A. 150
B. 225
C. 450
D. 750
E. 900

Since rectangle is inscribed in the circle. So. Diagonal of rectangle = diameter of circle = 7.5 $$\sqrt{2}$$ * 2 = 15 $$\sqrt{2}$$
Area of rectangle = 1/2 * diagonal^2 = 1/2 * $${(15\sqrt{2})}^2$$ = 225

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