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# rectangles and squares

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Manager
Affiliations: Beta Gamma Sigma
Joined: 14 Aug 2008
Posts: 209

Kudos [?]: 75 [0], given: 3

Schools: Harvard, Penn, Maryland

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24 May 2009, 21:07
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This topic is locked. If you want to discuss this question please re-post it in the respective forum.

The perimeters of a square region S and a rectangular region R are equal. If the sides of R are in the ratio of 2:3, what is the ratio of the area of region R to the area of Region S?

A) 25:16
B) 24:25
C) 5:6
D) 4:5
E) 4:9

Last edited by dk94588 on 25 May 2009, 06:40, edited 1 time in total.

Kudos [?]: 75 [0], given: 3

Senior Manager
Joined: 08 Jan 2009
Posts: 325

Kudos [?]: 180 [0], given: 5

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24 May 2009, 23:20
I thinks the question is area of R to S

4a = 2(2x + 3x)

a = 5x / 2

Ares of square S = a^2 = 25x^2/4

Ares of R = 2x * 3x = 6 x^2

So R : S = 6 x^2 / (25x^2/4) = 24 : 25

Ans B

Kudos [?]: 180 [0], given: 5

Manager
Affiliations: Beta Gamma Sigma
Joined: 14 Aug 2008
Posts: 209

Kudos [?]: 75 [0], given: 3

Schools: Harvard, Penn, Maryland

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25 May 2009, 06:41
yes it was, sorry just edited it

Kudos [?]: 75 [0], given: 3

Director
Joined: 27 Jun 2008
Posts: 540

Kudos [?]: 69 [0], given: 92

WE 1: Investment Banking - 6yrs

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25 May 2009, 07:13
B

I got the same question on GMAT Prep.

Kudos [?]: 69 [0], given: 92

Manager
Affiliations: Beta Gamma Sigma
Joined: 14 Aug 2008
Posts: 209

Kudos [?]: 75 [0], given: 3

Schools: Harvard, Penn, Maryland

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25 May 2009, 08:17
thats where its off of. They don't explain the answers so I was hoping someone here would, which they did. The answer is B.

Kudos [?]: 75 [0], given: 3

Re: rectangles and squares   [#permalink] 25 May 2009, 08:17
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