It is currently 22 Nov 2017, 00:38

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

Require assistance - how to solve this

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
Current Student
avatar
Joined: 26 May 2005
Posts: 554

Kudos [?]: 244 [0], given: 13

Re: Require assistance - how to solve this [#permalink]

Show Tags

New post 07 Jun 2011, 10:45
00:00
A
B
C
D
E

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions

HideShow timer Statistics

arryputtar wrote:
One of the angles of a triangle is 60° and length of its two sides is 6 cm and 7 cm. The length of the
third side of the triangle is
a. \sqrt{43} b. 3+\sqrt{22} + c. \sqrt{43} or 3 +\sqrt{22} d. None of these


I dont think this is tested on GMAT

formula is
a^2= b^2+C^2-2bc Cos A
a^2 = 36 + 49- 2*6*7*cos 60
a^2 = 36 + 49- 2*6*7*1/2
a^2 = 43
a = sqr 43.

hence A

Kudos [?]: 244 [0], given: 13

Manager
Manager
avatar
Joined: 08 Sep 2010
Posts: 159

Kudos [?]: 28 [0], given: 18

Re: Require assistance - how to solve this [#permalink]

Show Tags

New post 10 Jun 2011, 22:49
agree with sudhir. this is not tested on the GMAT.
If it was mentioned that its a right angled triangle etc then it would make sense.
_________________

My will shall shape the future. Whether I fail or succeed shall be no man's doing but my own.

If you like my explanations award kudos.

Kudos [?]: 28 [0], given: 18

Manager
Manager
User avatar
Joined: 28 Feb 2011
Posts: 82

Kudos [?]: 41 [0], given: 2

Re: Require assistance - how to solve this [#permalink]

Show Tags

New post 11 Jun 2011, 04:17
Thats a bit too formula-centric..dont think it would be tested..
Agree with the solution provided..
_________________

Fight till you succeed like a gladiator..or doom your life which can be invincible

Kudos [?]: 41 [0], given: 2

VP
VP
avatar
Status: There is always something new !!
Affiliations: PMI,QAI Global,eXampleCG
Joined: 08 May 2009
Posts: 1283

Kudos [?]: 286 [0], given: 10

Re: Require assistance - how to solve this [#permalink]

Show Tags

New post 14 Jun 2011, 01:33
well the above formula is derived.
Drop a perpendicular from A on to BC and name the point D.

now in triangle CDA, cos 60 = CD/AC = 1/2
CD = 3

thus AD^2 = 6^2-3^2 = 27
now in triangle BDA,
AB^2 = AD^2 + BD^2
BD = 7-3 = 4

thus AB^2 = 16 + 27 = 43.Hence.
_________________

Visit -- http://www.sustainable-sphere.com/
Promote Green Business,Sustainable Living and Green Earth !!

Kudos [?]: 286 [0], given: 10

Re: Require assistance - how to solve this   [#permalink] 14 Jun 2011, 01:33
Display posts from previous: Sort by

Require assistance - how to solve this

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  


GMAT Club MBA Forum Home| About| Terms and Conditions| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.