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# Right triangle PQR is to be constructed in the xy-plane so

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Senior Manager
Joined: 25 Nov 2006
Posts: 333

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Schools: St Gallen, Cambridge, HEC Montreal
Right triangle PQR is to be constructed in the xy-plane so [#permalink]

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02 Mar 2008, 14:11
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Right triangle PQR is to be constructed in the xy-plane so that the right triangle is at P and PR is parallel to the x-axis. The x- and y-coordinates of P, Q and R are to be integers that satisfy the inequalities -4≤x≤5 and 6≤y≤16. How many different triangles with these properties could be constructed?

A - 110
B - 1,100
C - 9,900
D - 10,000
E - 12,100

Kudos [?]: 70 [0], given: 0

Senior Manager
Joined: 25 Nov 2006
Posts: 333

Kudos [?]: 70 [0], given: 0

Schools: St Gallen, Cambridge, HEC Montreal
Re: OG PS - 248 [#permalink]

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06 Mar 2008, 05:39
I was thinking of solving this with Permutation or Combination?

Can anyone advice whether it's possible?

Kudos [?]: 70 [0], given: 0

Director
Joined: 14 Jan 2007
Posts: 775

Kudos [?]: 168 [0], given: 0

Re: OG PS - 248 [#permalink]

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06 Mar 2008, 09:23
As per the given conditions, P and Q are on the same vertical line.
PQ line can move 10 points horizontally.

P and R on the same horizontal line.
PR can be move 11 points vertically.

So total possible triangles = 10*11 =110

Kudos [?]: 168 [0], given: 0

Re: OG PS - 248   [#permalink] 06 Mar 2008, 09:23
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