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Robots X, Y, and Z each assemble components at their

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Robots X, Y, and Z each assemble components at their [#permalink]

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Robots X, Y, and Z each assemble components at their respective constant rates. If \(r_x\) is the ratio of Robot X's constant rate to Robot Z's constant rate and \(r_y\) is the ratio of Robot Y's constant rate to Robot Z's constant rate, is Robot Z's constant rate the greatest of the three?

(1) \(r_x < r_y\)
(2) \(r_y < 1\)

OPEN DISCUSSION OF THIS QUESTION IS HERE: robots-x-y-and-z-each-assemble-components-at-their-respect-139477.html
[Reveal] Spoiler: OA

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Re: Robots X, Y, and Z each assemble components at their [#permalink]

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ajit257 wrote:
see attachment

Can some explain the reasoning behind this ques.


Robots X, Y, and Z each assemble components at their respective constant rates. If rx is the ratio of robot X's constant rate to robot Z's constant rate and ry is the ratio of robot Y's constant rate to robot Z's constant rate, is robot Z's constant rate the greatest of the three?

Let the rates of robots X, Y, and Z be x, y, and z respectively. Given: \(r_x=\frac{x}{z}\) and \(r_y=\frac{y}{z}\). Question is \(z>x\) and \(z>y\)?

(1) \(r_x<r_y\) --> \(\frac{x}{z}<\frac{y}{z}\) --> \(x<y\). Not sufficient.

(2) \(r_y<1\) --> \(\frac{y}{z}<1\) --> \(y<z\). Not sufficient.

(1)+(2) As \(x<y\) and \(y<z\) then \(x<y<z\). Sufficient.

Answer: C.
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Re: Robots X, Y, and Z each assemble components at their [#permalink]

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New post 31 Mar 2009, 18:03
stmnt 1 - not suffic.
a<b => x/z < y/z => x< y
nothing about z

stmnt 2 - b<1 - not suffic.
nothing about a or z

let's combine - b<1 => a<b and a<1
still not sufficient, z could be >,= or < than a and/or b, and it would still satisfy stmnt 1 and 2.

I think it's E.

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Re: Robots X, Y, and Z each assemble components at their [#permalink]

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New post 01 Apr 2009, 00:18
for 1 and 2
a < b < 1
x/z < y/z < 1
denominator z is greater than numerator. Hence C is answer.

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Re: Robots X, Y, and Z each assemble components at their [#permalink]

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New post 01 Apr 2009, 01:27
I think E
Lets take V as Robot Z's constant rate

is Robot Z's constant rate the greatest of the three?

X:Y:Z=Va:Vb:V
now to have V highest we need to know whether V is <0 or >0
V could be 2 or say, 1/2
it changes the whole picture



Robots X, Y, and Z each assemble components in their respective constant rates. If a is the ration of Robot X's constant rate to Robot Z's constant rate and b is the ratio of Robot Y's constant rate to Robot Z's constant rate, is Robot Z's constant rate the greatest of the three.
1) a < b
2) b < 1
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Re: Robots X, Y, and Z each assemble components at their [#permalink]

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New post 01 Apr 2009, 15:39
My take is C

X:Z=a; Y:Z=b
Lets start with option 2 b<1
that means Z is bigger than Y.

1 says a<b so again Z is bigger than X.


Lets solve it by statements

Y= bZ Y is b times faster than Z if b is less than 1 then Z is faster on the similar note A can deduced.

@A Nitya .... Picture will not change as long as V is greater zero and V can not be negative as rate will always be positive.

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Re: Robots X, Y, and Z each assemble components at their [#permalink]

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New post 01 Apr 2009, 17:03
hemantsood wrote:
My take is C

X:Z=a; Y:Z=b
Lets start with option 2 b<1
that means Z is bigger than Y.

1 says a<b so again Z is bigger than X.


Lets solve it by statements

Y= bZ Y is b times faster than Z if b is less than 1 then Z is faster on the similar note A can deduced.

@A Nitya .... Picture will not change as long as V is greater zero and V can not be negative as rate will always be positive.


I think you reasoning is correct, the answer should be C, not E.

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Re: Robots X, Y, and Z each assemble components at their [#permalink]

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New post 03 Jan 2011, 20:26
We need both the information if the constant rate for Z is greater or not.
1. says that constant rate of Y is greater than X. x/z < x/y
2. says that constant rate of Y is smaller than Z. y/z <1

so we need both the information.

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Re: Robots X, Y, and Z each assemble components at their [#permalink]

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Re: Robots X, Y, and Z each assemble components at their [#permalink]

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New post 31 Aug 2015, 06:47
mrsmarthi wrote:
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Robots X, Y, and Z each assemble components at their respective constant rates. If \(r_x\) is the ratio of Robot X's constant rate to Robot Z's constant rate and \(r_y\) is the ratio of Robot Y's constant rate to Robot Z's constant rate, is Robot Z's constant rate the greatest of the three?

(1) \(r_x < r_y\)
(2) \(r_y < 1\)


OPEN DISCUSSION OF THIS QUESTION IS HERE: robots-x-y-and-z-each-assemble-components-at-their-respect-139477.html
_________________

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Collection of Questions:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

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Re: Robots X, Y, and Z each assemble components at their [#permalink]

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New post 25 Feb 2017, 15:16
Hello from the GMAT Club BumpBot!

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Re: Robots X, Y, and Z each assemble components at their   [#permalink] 25 Feb 2017, 15:16
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