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SQRT (16 + 16)^1/2 =

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Bunuel
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SQRT (16 + 16)^1/2 = [#permalink] New post  14 Jan 2014, 01:04
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The Official Guide For GMAT® Quantitative Review, 2ND Edition

\(\sqrt{16+16}=\)

(A) \(4\sqrt{2}\)
(B) \(8\sqrt{2}\)
(C) \(16\sqrt{2}\)
(D) 8
(E) 16

Problem Solving
Question: 36
Category: Arithmetic Operations on radical express ions
Page: 66
Difficulty: 500


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Bunuel
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Re: SQRT (16 + 16)^1/2 = [#permalink] New post  14 Jan 2014, 01:04
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SOLUTION

\(\sqrt{16+16}=\)

(A) \(4\sqrt{2}\)
(B) \(8\sqrt{2}\)
(C) \(16\sqrt{2}\)
(D) 8
(E) 16

\(\sqrt{16+16}=\sqrt{32}=\sqrt{16*2}=4\sqrt{2}\).

Answer: A.
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Re: SQRT (16 + 16)^1/2 = [#permalink] New post  14 Jan 2014, 09:19
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Bunuel wrote:
The Official Guide For GMAT® Quantitative Review, 2ND Edition

\(\sqrt{16+16}=\)

(A) \(4\sqrt{2}\)
(B) \(8\sqrt{2}\)
(C) \(16\sqrt{2}\)
(D) 8
(E) 16



Root(16*2) = root(16) * root(2) = 4*root(2). Option A)
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Re: SQRT (16 + 16)^1/2 = [#permalink] New post  14 Jan 2014, 22:04
1
Kudos
\sqrt{16+16} = \sqrt{2*16}
= 4\sqrt{2}

Ans is (A)
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Bunuel
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Re: SQRT (16 + 16)^1/2 = [#permalink] New post  18 Jan 2014, 05:44
Expert Reply
SOLUTION

\(\sqrt{16+16}=\)

(A) \(4\sqrt{2}\)
(B) \(8\sqrt{2}\)
(C) \(16\sqrt{2}\)
(D) 8
(E) 16

\(\sqrt{16+16}=\sqrt{32}=\sqrt{16*2}=4\sqrt{2}\).

Answer: A.
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JeffTargetTestPrep
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Re: SQRT (16 + 16)^1/2 = [#permalink] New post  06 Sep 2016, 11:09
Expert Reply
Bunuel wrote:
The Official Guide For GMAT® Quantitative Review, 2ND Edition

\(\sqrt{16+16}=\)

(A) \(4\sqrt{2}\)
(B) \(8\sqrt{2}\)
(C) \(16\sqrt{2}\)
(D) 8
(E) 16


Solution:

√(16 + 16)

√32

√16 x √2

4√2

Answer: A
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Esguitar
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Re: SQRT (16 + 16)^1/2 = [#permalink] New post  29 Jul 2017, 14:24
Hi
√16+16= √16(1+1)=√16*2= 4√2

Answer: A.
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pushpitkc
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Re: SQRT (16 + 16)^1/2 = [#permalink] New post  29 Jul 2017, 23:40
\(\sqrt{16+16} = \sqrt{32}\)
\(= \sqrt{2^5} = \sqrt{2^2 * 2^2 * 2} = 2*2\sqrt{2} = 4\sqrt{2}\)(Option A)
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Re: SQRT (16 + 16)^1/2 = [#permalink] New post  28 Oct 2022, 00:16
Hello from the GMAT Club BumpBot!

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