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Rules 1. Time yourself 2. Work your solution on a seperate

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CEO
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Joined: 15 Aug 2003
Posts: 3452

Kudos [?]: 924 [0], given: 781

Rules 1. Time yourself 2. Work your solution on a seperate [#permalink]

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New post 10 Mar 2004, 20:23
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Rules

1. Time yourself
2. Work your solution on a seperate sheet of paper
3. write your solution here , and your time please.

If the square root of the product of three distinct positive
integers is equal to the largest of the three numbers, what is the
product of the two smaller numbers?

(1) The largest number is 12.
(2) The average (arithmetic mean) of the three numbers is 20/3

Kudos [?]: 924 [0], given: 781

Director
Director
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Joined: 03 Jul 2003
Posts: 651

Kudos [?]: 106 [0], given: 0

 [#permalink]

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New post 10 Mar 2004, 20:58
Ans: D

Time more than 4 mins

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Manager
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A.. [#permalink]

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New post 10 Mar 2004, 21:58
I think it it is A..2 min

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Manager
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New post 10 Mar 2004, 23:50
I will go for A (only statement 1 can be used to answer).
Time taken 30 seconds.

Sol. Three integers be X,Y,Z and largest be Z.
sqrt(XYZ) = Z ,replace Z by 12
sqrt(XY*12) = 12
or sqrt(XY) = sqrt(12)
or XY = 12

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Director
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 [#permalink]

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New post 11 Mar 2004, 03:40
Agree with mantha and mdfrahim, think that the answer is A)
Time: 2,5 min.

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SVP
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New post 11 Mar 2004, 05:42
a) sqrt( a * b * 12 ) = 12
so a * b = 12
Sufficient
b) a+b+c = 20
Only number that satisfies this and a * b = c is c = 12
Sufficient
< 2 minutes

Kudos [?]: 114 [0], given: 0

CEO
CEO
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Joined: 15 Aug 2003
Posts: 3452

Kudos [?]: 924 [0], given: 781

Re: [#18] 2 Min. Challenge : Product [#permalink]

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New post 11 Mar 2004, 06:30
praetorian123 wrote:
Rules

1. Time yourself
2. Work your solution on a seperate sheet of paper
3. write your solution here , and your time please.

If the square root of the product of three distinct positive
integers is equal to the largest of the three numbers, what is the
product of the two smaller numbers?

(1) The largest number is 12.
(2) The average (arithmetic mean) of the three numbers is 20/3



D is correct

good work anand :)

Kudos [?]: 924 [0], given: 781

Senior Manager
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Joined: 23 Sep 2003
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 [#permalink]

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New post 11 Mar 2004, 06:51
I agree with Anandnk and Kpadma.

D is the answer.

The only distinct positive integers that satisfy the requirement that their sum = 20, and that the largest integer = the product of the other 2 integers are 6, 2 and 12.

If you try other combinations, you'll find that they don't sum to 20. Example: a=3; b=4 ; ab = c = 12 but 3 + 4 + 12 <> 20. Same with 8, 2 and 16.

Kudos [?]: 4 [0], given: 0

  [#permalink] 11 Mar 2004, 06:51
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