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# Running at the same constant rate, 6 identical machines can

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Intern
Joined: 08 Sep 2005
Posts: 44

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Running at the same constant rate, 6 identical machines can [#permalink]

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15 Apr 2006, 20:13
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Running at the same constant rate, 6 identical machines can produce a total of 270 bottles per minute. At this rate, how many bottles could 10 such machines produce in 4 minutes?

A) 648
B) 1,800
C) 2,700
D) 10,800
E) 64,800

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Manager
Joined: 09 Feb 2006
Posts: 129

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Location: New York, NY

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16 Apr 2006, 06:08
Okay, first let's figure out the rate of 6 machines. Work=rate*time

So in 1 minute, they produce 270 bottles. Therefore their combined rate 270. To find the rate of each machine, we could divide this by 6 and multiply by ten, OR we could multiply by 5/3 (because we're adding an additional 2/3 of machines). Either way, we would find that their rate is 450 bottles per minute. Now we multiply by 4, which yields 1,800. Answer is B.

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Director
Joined: 10 Oct 2005
Posts: 713

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16 Apr 2006, 07:25
6 machines 270 bottles a minute hence 1 machine 270/6
(270/6)*10*4=1800don't have to multiply all this numbers just use the simplification
total 1 min
jcgoodchild your second approach is really something))I think we have new math guru here))Thank you!
_________________

IE IMBA 2010

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16 Apr 2006, 07:25
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