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# S represents the sum of the weights of n fish in pounds.

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Manager
Joined: 17 Aug 2006
Posts: 87

Kudos [?]: 20 [0], given: 0

S represents the sum of the weights of n fish in pounds. [#permalink]

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13 Nov 2008, 05:40
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S represents the sum of the weights of n fish in pounds. Which of the following represents the average (arithmetic mean) of the n weights in ounces? (1pound = 16 ounces)

Kudos [?]: 20 [0], given: 0

Manager
Joined: 17 Aug 2006
Posts: 87

Kudos [?]: 20 [0], given: 0

Re: prep 14 or 37 [#permalink]

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13 Nov 2008, 13:03
Yes, I believe that is because to get the average you divide the sum by the # and the 16 is the conversion correct.

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Manager
Joined: 05 Nov 2010
Posts: 63

Kudos [?]: 1 [0], given: 5

Re: prep 14 or 37 [#permalink]

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13 Dec 2010, 22:00
Can anyone give a full explanation instead of just the answers please? The answers are given in the GMAT Prep test, not the explanations.

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Math Expert
Joined: 02 Sep 2009
Posts: 41640

Kudos [?]: 124200 [1], given: 12075

Re: prep 14 or 37 [#permalink]

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14 Dec 2010, 01:50
1
KUDOS
Expert's post
spyguy wrote:
Can anyone give a full explanation instead of just the answers please? The answers are given in the GMAT Prep test, not the explanations.

S represents the sum of the weights of n fish in pounds. Which of the following represents the average (arithmetic mean) of the n weights in ounces? (1pound = 16 ounces)

As the sum of n fish in pounds is S pounds and 1 pound = 16 ounces then the sum of n fish in ounces will be 16S ounces.

So, average wight of n fish in onces is average=(sum of weights is ounces)/(# of fish)=16S/n.

Hope it's clear.
_________________

Kudos [?]: 124200 [1], given: 12075

Manager
Joined: 05 Nov 2010
Posts: 63

Kudos [?]: 1 [0], given: 5

Re: prep 14 or 37 [#permalink]

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14 Dec 2010, 08:51
It's very clear. Not sure why this one even held me up. Think it was one of those long study nights where even the mundane and easy seem like a never ending brick wall that you are trying to climb. Thanks Bunuel. +1 buddy and kudos.

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Director
Joined: 03 Sep 2006
Posts: 869

Kudos [?]: 1029 [0], given: 33

Re: prep 14 or 37 [#permalink]

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14 Dec 2010, 21:37
average = s/n

in ounce, the average = $$(s*16)/n$$

Kudos [?]: 1029 [0], given: 33

Re: prep 14 or 37   [#permalink] 14 Dec 2010, 21:37
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