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# Say I have the equation: x^2 = -2x I am tempted to simply

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Say I have the equation: x^2 = -2x I am tempted to simply [#permalink]

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25 Sep 2007, 19:38
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Say I have the equation: x^2 = -2x

I am tempted to simply divide each side by x, which results in: x = -2

But I understand that to be an incomplete solution. If I simplify differently, I wind up with:

x^2 = -2x
x^2 + 2x = 0
x(x + 2) = 0

Hence x = 0, -2.

Can anyone please explain this to me conceptually? How can I avoid repeating this mistake? Should I ALWAYS try to set up exponential equations by putting 0 (zero) on one side and all other terms on the other side, i.e.

POLYNOMIAL = 0

?

Thanks,
GeoMATrace

Last edited by geomatrace on 25 Sep 2007, 20:07, edited 1 time in total.
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25 Sep 2007, 20:01
geomatrace wrote:
Say I have the equation: x^2 = -2x

I am tempted to simply divide each side by x, which results in: x = -2

But I understand that to be an incomplete solution. If I simply differently, I wind up with:

x^2 = -2x
x^2 + 2x = 0
x(x + 2) = 0

Hence x = 0, -2.

Can anyone please explain this to me conceptually? How can I avoid repeating this mistake? Should I ALWAYS try to set up exponential equations by putting 0 (zero) on one side and all other terms on the other side, i.e.

POLYNOMIAL = 0

?

Thanks,
GeoMATrace

Yes. u should b/c when u use the method u first showed, then ur eliminating a value of X.
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25 Sep 2007, 20:11
geomatrace wrote:
Say I have the equation: x^2 = -2x

I am tempted to simply divide each side by x, which results in: x = -2

But I understand that to be an incomplete solution. If I simply differently, I wind up with:

x^2 = -2x
x^2 + 2x = 0
x(x + 2) = 0

Hence x = 0, -2.

Can anyone please explain this to me conceptually? How can I avoid repeating this mistake? Should I ALWAYS try to set up exponential equations by putting 0 (zero) on one side and all other terms on the other side, i.e.

POLYNOMIAL = 0

?

Thanks,
GeoMATrace

In short the answer is YES, you have to equate a polynomial to a zero, by bringing all the terms to LHS. Solving by bringing all the variables in a polynomial equation to the LHS allows you to extract all the "real" roots of the equation, if they exist. Now, there are equations like x^2+1 which does not have real roots but that's besides the point.

By solving equations the way you are solving you are not guaranteed to find all the roots of the equation. Clearly from you own example, you have seen that by using your method "0" is not seen as one of the roots of the equation.

HTH
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