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Seed mixture X is 40 percent ryegrass and 60 percent

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Intern
Joined: 27 Nov 2004
Posts: 30

Kudos [?]: 19 [0], given: 0

Location: Vienna, Austria
Seed mixture X is 40 percent ryegrass and 60 percent [#permalink]

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22 Jan 2005, 14:42
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Seed mixture X is 40 percent ryegrass and 60 percent bluegrass by weight; seed mixture Y is 25 percent ryegrass and 75 percent fescue. If a mixture of X and Y contains 30 percent ryegrass, what percent of the weight of this mixture is X ?

(A) 10%
(B) 33,3%
(C) 40%
(D) 50%
(E) 66,67%

pls explain. thanks. f.

Kudos [?]: 19 [0], given: 0

Director
Joined: 07 Jun 2004
Posts: 610

Kudos [?]: 922 [0], given: 22

Location: PA

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22 Jan 2005, 16:53
I am getting 33.33 % let me know if thats correct i will explain

thanks!

Kudos [?]: 922 [0], given: 22

Intern
Joined: 27 Nov 2004
Posts: 30

Kudos [?]: 19 [0], given: 0

Location: Vienna, Austria

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22 Jan 2005, 17:02
ole ole...correct, rx!!

pls explain...

THANKS

Kudos [?]: 19 [0], given: 0

Director
Joined: 07 Jun 2004
Posts: 610

Kudos [?]: 922 [0], given: 22

Location: PA

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22 Jan 2005, 18:21
the way i approcahed is in 2 steps

given .4x + .25y / x + y = 30% = .3

solve it u will get x=.5y from ------------ I

also we have to find percentage of x in the mixture

x / x + y from I

we get x / x + 2x = 1/3 = 33.33%

Kudos [?]: 922 [0], given: 22

22 Jan 2005, 18:21
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