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Selected Books

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Manager
Joined: 29 May 2008
Posts: 111

Kudos [?]: 126 [0], given: 0

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17 Sep 2009, 10:34
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In how many ways can 2 or more books be selected from a set of 5 offered by a book club?

A) 32
B) 26
C) 25
D) 20
E) 10

Kudos [?]: 126 [0], given: 0

Senior Manager
Joined: 23 Jun 2009
Posts: 360

Kudos [?]: 134 [0], given: 80

Location: Turkey
Schools: UPenn, UMich, HKS, UCB, Chicago

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17 Sep 2009, 11:42
TheRob wrote:
In how many ways can 2 or more books be selected from a set of 5 offered by a book club?

A) 32
B) 26
C) 25
D) 20
E) 10

Total number of groups is 2^5=32
0 books can be selected only one way
1 books can be selected 5C1 = 5 ways.
So 2 or more books can be selected 32-5-1=26 ways.
B

Kudos [?]: 134 [0], given: 80

Senior Manager
Joined: 18 Aug 2009
Posts: 317

Kudos [?]: 354 [0], given: 13

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17 Sep 2009, 12:52
Not sure if this is the correct way:

2 books out of 5 books can be selected in 5C2 ways = 10
3 books out of 5 books can be selected in 5C3 ways = 10
4 books out of 5 books can be selected in 5C4 ways = 5
5 books out of 5 books can be selected in 5C5 ways = 1

Total number of ways in which 2 or more books can be selected = 10+10+5+1 = 26.

Please correct me if I am wrong.

Kudos [?]: 354 [0], given: 13

Manager
Joined: 29 May 2008
Posts: 111

Kudos [?]: 126 [0], given: 0

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17 Sep 2009, 13:00

Kudos [?]: 126 [0], given: 0

Senior Manager
Joined: 18 Aug 2009
Posts: 317

Kudos [?]: 354 [0], given: 13

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17 Sep 2009, 13:03
maliyeci wrote:
hgp2k wrote:
Not sure if this is the correct way:

2 books out of 5 books can be selected in 5C2 ways = 10
3 books out of 5 books can be selected in 5C3 ways = 10
4 books out of 5 books can be selected in 5C4 ways = 5
5 books out of 5 books can be selected in 5C5 ways = 1

Total number of ways in which 2 or more books can be selected = 10+10+5+1 = 26.

Please correct me if I am wrong.

it is correct.

Thank you maliyeci!

Kudos [?]: 354 [0], given: 13

Re: Selected Books   [#permalink] 17 Sep 2009, 13:03
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