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# Series

Author Message
Intern
Joined: 28 Nov 2005
Posts: 33
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07 Oct 2007, 09:10
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

How would you solve :
4^(1/2)+4^(1/3)+4^(1/4) ?

Thanks.
Director
Joined: 11 Jun 2007
Posts: 920
Followers: 1

Kudos [?]: 207 [0], given: 0

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07 Oct 2007, 09:26
hidalgo01 wrote:
How would you solve :
4^(1/2)+4^(1/3)+4^(1/4) ?

Thanks.

not sure if this is the right logic:

4^(1/2) = 2
4^(1/3) = (2^2)^(1/3) = 2^2/3
4^(1/4) = (2^2)^(1/4) = 2^2/4 = sqrt 2

to simplify further:
2 + sqrt 2(2^1/6 + 1)

thats as far as i could go...
VP
Joined: 09 Jul 2007
Posts: 1100
Location: London
Followers: 6

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08 Oct 2007, 15:11
question seems out of gmat league if the answer is compacter than beckee's
Director
Joined: 08 Jun 2007
Posts: 576
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08 Oct 2007, 20:04
hidalgo01 wrote:
How would you solve :
4^(1/2)+4^(1/3)+4^(1/4) ?

Thanks.

We need options to arrive at a solution.
Re: Series   [#permalink] 08 Oct 2007, 20:04
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