It is currently 27 Jun 2017, 00:16

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# Set A = , If the median is x/2, what is x

Author Message
CEO
Joined: 21 Jan 2007
Posts: 2739
Location: New York City
Set A = , If the median is x/2, what is x [#permalink]

### Show Tags

29 Jan 2008, 13:17
1
This post was
BOOKMARKED
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Set A = [-x, -1, 1, 3, x],
If the median is x/2, what is x?
_________________

You tried your best and you failed miserably. The lesson is 'never try'. -Homer Simpson

CEO
Joined: 29 Mar 2007
Posts: 2559

### Show Tags

29 Jan 2008, 13:24
bmwhype2 wrote:
Set A = [-x, -1, 1, 3, x],
If the median is x/2, what is x?

are these in order by value? or is it just random? I don't see how it could be in order by value b/c that would mean x/2=1 and x=2, which wouldnt make any sense at all.

I get 0=x

b/c if we have -1,-x... then x must be less than 1 so---> -1,-x,x,1,3 thus x=x/2 --> 2x=x Only way this can be is if x=0.
VP
Joined: 05 Aug 2007
Posts: 1499
Schools: NYU Stern '11

### Show Tags

29 Jan 2008, 13:25
I am assuming x is an integer.

If the median of a set of 5 integers is x/2, then x/2 is the "middle" integer when all integers are arranged in increasing order.

so we have, -1, 1, x/2, 3, x. x must logically be the largest integer in the set if x/2 is the median.

Therefore, x must be 4.

Part of me thinks this was almost too easy, so please correct me if I made a mistake somewhere.
CEO
Joined: 17 Nov 2007
Posts: 3584
Concentration: Entrepreneurship, Other
Schools: Chicago (Booth) - Class of 2011
GMAT 1: 750 Q50 V40

### Show Tags

29 Jan 2008, 13:32
Set A = [-x, -1, 1, 3, x]

Set A have 5 numbers, Therefore, median is defined by one number: 1 or x (x<1)

1) x/2=1 ==> x=2
2) x/2=x ==> x=0
_________________

HOT! GMAT TOOLKIT 2 (iOS) / GMAT TOOLKIT (Android) - The OFFICIAL GMAT CLUB PREP APP, a must-have app especially if you aim at 700+ | PrepGame

VP
Joined: 05 Aug 2007
Posts: 1499
Schools: NYU Stern '11

### Show Tags

29 Jan 2008, 13:33
Wait, so Set A is already arranged in increasing order?
CEO
Joined: 21 Jan 2007
Posts: 2739
Location: New York City

### Show Tags

29 Jan 2008, 13:39
walker wrote:
Set A = [-x, -1, 1, 3, x]

Set A have 5 numbers, Therefore, median is defined by one number: 1 or x (x<1)

1) x/2=1 ==> x=2
2) x/2=x ==> x=0

can you elaborate? if x=0, then 0/2 because median is is x/2
_________________

You tried your best and you failed miserably. The lesson is 'never try'. -Homer Simpson

Senior Manager
Joined: 26 Jan 2008
Posts: 263

### Show Tags

29 Jan 2008, 13:40
bmwhype2 wrote:
Set A = [-x, -1, 1, 3, x],
If the median is x/2, what is x?

can you provide the answer choices?

0 and 2 both seem to work..
_________________
CEO
Joined: 21 Jan 2007
Posts: 2739
Location: New York City

### Show Tags

29 Jan 2008, 13:43
incognito1 wrote:
bmwhype2 wrote:
Set A = [-x, -1, 1, 3, x],
If the median is x/2, what is x?

can you provide the answer choices?

0 and 2 both seem to work..

this is part of a DS question. both are correct. i just want to see how the answer came about.
_________________

You tried your best and you failed miserably. The lesson is 'never try'. -Homer Simpson

CEO
Joined: 17 Nov 2007
Posts: 3584
Concentration: Entrepreneurship, Other
Schools: Chicago (Booth) - Class of 2011
GMAT 1: 750 Q50 V40

### Show Tags

29 Jan 2008, 13:45
I guess choices are like

I. 0
II 1
III 2

A only I
B only II
C I and III
D II and III
E I, II and III

_________________

HOT! GMAT TOOLKIT 2 (iOS) / GMAT TOOLKIT (Android) - The OFFICIAL GMAT CLUB PREP APP, a must-have app especially if you aim at 700+ | PrepGame

CEO
Joined: 29 Mar 2007
Posts: 2559

### Show Tags

29 Jan 2008, 13:47
walker wrote:
Set A = [-x, -1, 1, 3, x]

Set A have 5 numbers, Therefore, median is defined by one number: 1 or x (x<1)

1) x/2=1 ==> x=2
2) x/2=x ==> x=0

Ah yes, 2 can be an answer as well. -2,-1,1,2,3 And thus 2/2=1 is the median.

or -1,0,0,1,3. But in either case the original is not in the correct increasing order.

Haven't done a question quite like this before. whats the source?
Senior Manager
Joined: 26 Jan 2008
Posts: 263

### Show Tags

29 Jan 2008, 14:39
walker wrote:
I guess choices are like

I. 0
II 1
III 2

A only I
B only II
C I and III
D II and III
E I, II and III

lol didn't realize this was a DS question
_________________
SVP
Joined: 28 Dec 2005
Posts: 1558

### Show Tags

29 Jan 2008, 20:29
i just assumed that set was already in increasing order. since there are an odd number of terms, the median is equal to 1, and if 1=x/2, that leads to x=2 .... am i oversimplifying this q ?
CEO
Joined: 21 Jan 2007
Posts: 2739
Location: New York City

### Show Tags

05 Feb 2008, 06:17
walker wrote:
Set A = [-x, -1, 1, 3, x]

Set A have 5 numbers, Therefore, median is defined by one number: 1 or x (x<1)

1) x/2=1 ==> x=2
2) x/2=x ==> x=0

thanks. finally figured out the logic...
_________________

You tried your best and you failed miserably. The lesson is 'never try'. -Homer Simpson

Director
Joined: 01 Jan 2008
Posts: 622

### Show Tags

05 Feb 2008, 07:52
bmwhype2 wrote:
Set A = [-x, -1, 1, 3, x],
If the median is x/2, what is x?

x >= 0 because there are at least 3 numbers that are greater or equal than 0 and x/2 is the median.

1) x - median -> x = x/2 -> x = 0
2) 1 - median -> x/2 = 1 -> x = 2

there are no other options because the median is greater or equal than zero and it can't be equal to 3 because there are at least 3 numbers smaller than 3.
Director
Joined: 01 May 2007
Posts: 793

### Show Tags

05 Feb 2008, 15:07
I assumed this set wasn't in order. and the value of x was the same integer. for -x equals -2 and x = 2. so I rearranged..

Set A = ( -2, -1, 1, 2, 3)

Median being 1.
Re: median   [#permalink] 05 Feb 2008, 15:07
Display posts from previous: Sort by