Check GMAT Club Decision Tracker for the Latest School Decision Releases https://gmatclub.com/AppTrack

 It is currently 25 May 2017, 12:59

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# Set Q consists of 4 consecutive integers, while set T

Author Message
GMAT Instructor
Joined: 04 Jul 2006
Posts: 1263
Followers: 29

Kudos [?]: 307 [0], given: 0

Set Q consists of 4 consecutive integers, while set T [#permalink]

### Show Tags

27 Aug 2006, 07:38
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions

### HideShow timer Statistics

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Set Q consists of 4 consecutive integers, while set T consists of 7 consecutive integers. If the sum of the integers in Q is equal to the sum of the integers in T, is the median of the elements in T a positive number?

(1) Q is a subset of T.
(2) The largest integer in set Q is also in set T.

Last edited by kevincan on 27 Aug 2006, 08:19, edited 2 times in total.
Intern
Joined: 24 Jun 2006
Posts: 47
Followers: 0

Kudos [?]: 0 [0], given: 0

Re: DS: Sets of Consecutive Integers [#permalink]

### Show Tags

27 Aug 2006, 07:51
kevincan wrote:
Set Q consists of 4 consecutive integers, while set T consists of 7 consecutive integers. What is the sum of the elements in Q?

(1) Q is a subset of S.
(2) The largest integer in set Q is also in set S.

Are u sure that the question is correct? Seems like it should be T instead of S. well, whatever it is, do let me know!

SHA
GMAT Instructor
Joined: 04 Jul 2006
Posts: 1263
Followers: 29

Kudos [?]: 307 [0], given: 0

### Show Tags

27 Aug 2006, 08:20
GMATT73 wrote:
E?

You're right, but I left out part of the question. Now corrected!
GMAT Instructor
Joined: 04 Jul 2006
Posts: 1263
Followers: 29

Kudos [?]: 307 [0], given: 0

### Show Tags

28 Aug 2006, 05:59
Question has been corrected. Let's try now!
VP
Joined: 02 Jun 2006
Posts: 1261
Followers: 2

Kudos [?]: 87 [0], given: 0

### Show Tags

28 Aug 2006, 10:03
Let Q = {n, n+1, n+2, n+3}
Let T = {k, k+1, k+2, .., k+6}

Given
Sum Q = Sum T
4n+(1+2+3) = 7k+(1+2+3..6)
4n = 7k+(4+5+6)

4n=7k+15...........(1)

Q: Is median of T > 0?
i.e. k+3 > 0 i.e. k >-3

Is k > -3?

S1: Q subset of T
Therefore, Q is part of T
n can be {k, k+1, k+2, k+3}

Solving (1) with values for n:
a. n=k:
-3k = 15 => k = -5 < -3.

b.n=k+1
4k+4 = 7k+15
-3k = 11; k is integer. Not possible.

c. n=k+2
4k+8 = 7k+15
or -3k=7 Not possible

d. n=k+3
4k+12 = 7k+15
-3k=3=> k=-1 > -3

Not sufficient as two conflicting answers from (a) and (d)

S2: n+3 belongs to T
n+3 can be anyone of the elements of the set T

a. n+3 = k
4k-12 = 7k+15
-3k = 27, k=-9 < -3

b. n+3 = k+1
4k-8 =7k+15
-3k=23 Not possible

c. n+3 = k+2
4k-4 = 7k+15
-3k = 19 Not possible

d. n+3 = k+3
-3k = 15, k = -5 < -3

e. n+3 = k+4
4k+4 = 7k+15
-3k = 11 Not possible

f. n+3 = k+5
4k+8 = 7k+15
-3k = 7 Not possible

g. n+3 = k+6
4k+12 = 7k+15
-3k = 3, k = -1 > -3

From (a), (d), (g) conflicting answers.

Not sufficient.

S1 & S2:
n+3 = k+3 => k = -5 < -3
n+3 = k+4 => Not possible
n+3 = k+5 => Not possible
n+3 = k+6 => k = -1 > -3

Not sufficient.

28 Aug 2006, 10:03
Display posts from previous: Sort by