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Set R contains five numbers that have an average value of 55 [#permalink]
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Set R contains five numbers that have an average value of 55. If the median of the set is equal to the mean, and the largest number in the set is equal to 20 more than three times the smallest number, what is the largest possible range for the numbers in the set? A. 78 B. 77 1/5 C. 66 1/7 D. 55 1/7 E. 52
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Last edited by Bunuel on 10 Jun 2012, 01:25, edited 1 time in total.
Edited the question and added the OA



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Re: Largest possible range in Set R [#permalink]
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Orange08 wrote: Set R contains five numbers that have an average value of 55. If the median of the set is equal to the mean, and the largest number in the set is equal to 20 more than three times the smallest number, what is the largest possible range for the numbers in the set?
78 77 1/5 66 1/7 55 1/7 52 {\(a_1\), \(a_2\), \(a_3\), \(a_4\), \(a_5\)} As mean of 5 numbers is 55 then the sum of these numbers is \(5*55=275\); The median of the set is equal to the mean > \(mean=median=a_3=55\); The largest number in the set is equal to 20 more than three times the smallest number > \(a_5=3a_1+20\). So our set is {\(a_1\), \(a_2\), \(55\), \(a_4\), \(3a_1+20\)} and \(a_1+a_2+55+a_4+3a_1+20=275\). The range of a set is the difference between the largest and smallest elements of a set.\(Range=a_5a_1=3a_1+20a_1=2a_1+20\) > so to maximize the range we should maximize the value of \(a_1\) and to maximize \(a_1\) we should minimize all other terms so \(a_2\) and \(a_4\). Min possible value of \(a_2\) is \(a_1\) and min possible value of \(a_4\) is \(median=a_3=55\) > set becomes: {\(a_1\), \(a_1\), \(55\), \(55\), \(3a_1+20\)} > \(a_1+a_1+55+55+3a_1+20=275\) > \(a_1=29\) > \(Range=2a_1+20=78\) Answer: A.
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Re: Largest possible range in Set R [#permalink]
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I took the set to be m, m, 55, 55, 3m+20. (second value has to be minimum possible  m, and fourth value has to be minimum possible  55). now average is 55 so 55 = (6m + 130)/5 which gives m = 29, and 3m+20=107 so range is largest  smallest = 10729 = 78
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Re: Largest possible range in Set R [#permalink]
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Let smallest # = x, Largest = 3x + 20 So range = 2x + 20 x, x, 55, 55, 3x+20, For Max range lowest should be as low as possible and highest should be as high as possible also, the 2nd value has to be minimized, so it is x, the fourth value also ahs to be kept at minimum, so it is 55 3x + 20 + 110 + 2x = 275 => 5x = 275  130 = 145 => x = 29 , so range = 29*2 + 20 = 78 So answer is A.
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Re: Largest possible range in Set R [#permalink]
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Backsolving : Range = 2a + 20 where a = first number.
Hence the answer is even and highest options. It should be A.



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Re: Largest possible range in Set R [#permalink]
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08 Mar 2011, 15:51
gmat1220 wrote: Backsolving : Range = 2a + 20 where a = first number.
Hence the answer is even and highest options. It should be A. That's an awesome application of number properties to solve this question is seconds. Kudos



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Set R contains five numbers that have an average value of 55 [#permalink]
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Re: Largest possible range in Set R [#permalink]
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08 Mar 2011, 16:19
Bunuel wrote: Yalephd wrote: gmat1220 wrote: Backsolving : Range = 2a + 20 where a = first number.
Hence the answer is even and highest options. It should be A. That's an awesome application of number properties to solve this question is seconds. Kudos That's not correct. Yes, the range equals to 2a+20 but without any further calculation we can not say whether it must be even, for example if a is not an integer then 2a+20 can be odd or not an integer at all. Also the answer is not necessarily the highest option, it just happened to be so in this particular case. Thanks. Assuming that A is an integer is where I erred.



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Re: Largest possible range in Set R [#permalink]
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08 Mar 2011, 17:54
I was back solving  to confirm the answer. x^2 = 4 Implies x is not necessarily 2. It can be 2



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Re: Largest possible range in Set R [#permalink]
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max range will be when 55*3 = 165 will give 110 as range.But the value isn't present. Hence go for two small numbers , 55*2 and largest number combination. thus 2x+110 + 3x+20 = 275 will give, x= 29 and 3x+20 = 97. Range = 78.
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Re: Largest possible range in Set R [#permalink]
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01 May 2011, 23:16
max range will be when 55*3 = 165 will give 110 as range.But the value isn't present. Hence go for two small numbers , 55*2 and largest number combination. thus 2x+110 + 3x+20 = 275 will give, x= 29 and 3x+20 = 97. Range = 78.
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Re: Largest possible range in Set R [#permalink]
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18 Nov 2011, 04:18
Bunuel wrote: Orange08 wrote: Set R contains five numbers that have an average value of 55. If the median of the set is equal to the mean, and the largest number in the set is equal to 20 more than three times the smallest number, what is the largest possible range for the numbers in the set?
78 77 1/5 66 1/7 55 1/7 52 {\(a_1\), \(a_2\), \(a_3\), \(a_4\), \(a_5\)} As mean of 5 numbers is 55 then the sum of these numbers is \(5*55=275\); The median of the set is equal to the mean > \(mean=median=a_3=55\); The largest number in the set is equal to 20 more than three times the smallest number > \(a_5=3a_1+20\). So our set is {\(a_1\), \(a_2\), \(55\), \(a_4\), \(3a_1+20\)} and \(a_1+a_2+55+a_4+3a_1+20=275\). The range of a set is the difference between the largest and smallest elements of a set.\(Range=a_5a_1=3a_1+20a_1=2a_1+20\) > so to maximize the range we should maximize the value of \(a_1\) and to maximize \(a_1\) we should minimize all other terms so \(a_2\) and \(a_4\). Min possible value of \(a_2\) is \(a_1\) and min possible value of \(a_4\) is \(median=a_3=55\) > set becomes: {\(a_1\), \(a_1\), \(55\), \(55\), \(3a_1+20\)} > \(a_1+a_1+55+55+3a_1+20=275\) > \(a_1=29\) > \(Range=2a_1+20=78\) Answer: A. my approach was like yours, but it took me 6 min!!!



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Re: Largest possible range in Set R [#permalink]
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01 Nov 2012, 08:01
Bunuel wrote: Orange08 wrote: Set R contains five numbers that have an average value of 55. If the median of the set is equal to the mean, and the largest number in the set is equal to 20 more than three times the smallest number, what is the largest possible range for the numbers in the set?
78 77 1/5 66 1/7 55 1/7 52 {\(a_1\), \(a_2\), \(a_3\), \(a_4\), \(a_5\)} As mean of 5 numbers is 55 then the sum of these numbers is \(5*55=275\); The median of the set is equal to the mean > \(mean=median=a_3=55\); The largest number in the set is equal to 20 more than three times the smallest number > \(a_5=3a_1+20\). So our set is {\(a_1\), \(a_2\), \(55\), \(a_4\), \(3a_1+20\)} and \(a_1+a_2+55+a_4+3a_1+20=275\). The range of a set is the difference between the largest and smallest elements of a set.\(Range=a_5a_1=3a_1+20a_1=2a_1+20\) > so to maximize the range we should maximize the value of \(a_1\) and to maximize \(a_1\) we should minimize all other terms so \(a_2\) and \(a_4\). Min possible value of \(a_2\) is \(a_1\) and min possible value of \(a_4\) is \(median=a_3=55\) > set becomes: {\(a_1\), \(a_1\), \(55\), \(55\), \(3a_1+20\)} > \(a_1+a_1+55+55+3a_1+20=275\) > \(a_1=29\) > \(Range=2a_1+20=78\) Answer: A. Bunuel sir.. few questions that cums in my mnd like ..y did bunuel take A1 is equal to A2..and y didnt he take a2=55 instead of A4=55? i got lots of questions like this and i cant give ans correctly.. Thank u in advance bunuel..
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Re: Largest possible range in Set R [#permalink]
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02 Nov 2012, 05:17
sanjoo wrote: Bunuel wrote: Orange08 wrote: Set R contains five numbers that have an average value of 55. If the median of the set is equal to the mean, and the largest number in the set is equal to 20 more than three times the smallest number, what is the largest possible range for the numbers in the set?
78 77 1/5 66 1/7 55 1/7 52 {\(a_1\), \(a_2\), \(a_3\), \(a_4\), \(a_5\)} As mean of 5 numbers is 55 then the sum of these numbers is \(5*55=275\); The median of the set is equal to the mean > \(mean=median=a_3=55\); The largest number in the set is equal to 20 more than three times the smallest number > \(a_5=3a_1+20\). So our set is {\(a_1\), \(a_2\), \(55\), \(a_4\), \(3a_1+20\)} and \(a_1+a_2+55+a_4+3a_1+20=275\). The range of a set is the difference between the largest and smallest elements of a set.\(Range=a_5a_1=3a_1+20a_1=2a_1+20\) > so to maximize the range we should maximize the value of \(a_1\) and to maximize \(a_1\) we should minimize all other terms so \(a_2\) and \(a_4\). Min possible value of \(a_2\) is \(a_1\) and min possible value of \(a_4\) is \(median=a_3=55\) > set becomes: {\(a_1\), \(a_1\), \(55\), \(55\), \(3a_1+20\)} > \(a_1+a_1+55+55+3a_1+20=275\) > \(a_1=29\) > \(Range=2a_1+20=78\) Answer: A. Bunuel sir.. few questions that cums in my mnd like ..y did bunuel take A1 is equal to A2..and y didnt he take a2=55 instead of A4=55? i got lots of questions like this and i cant give ans correctly.. Thank u in advance bunuel.. After some steps we have that our set in ascending order is {\(a_1\), \(a_2\), \(55\), \(a_4\), \(3a_1+20\)} and \(Range=2a_1+20\). We need to maximize \(Range=2a_1+20\), thus we need to maximize \(a_1\) and to maximize \(a_1\) we should minimize all other terms so \(a_2\) and \(a_4\) (remember the sum of the terms is fixed, so we cannot just make \(a_1\) as large as we want). Now, since the set is in ascending order min possible value of \(a_2\) is \(a_1\) (it cannot be less than the first term) and min possible value of \(a_4\) is \(median=a_3=55\) (it cannot be less than the third term). Similar questions to practice:iftheaverageof5positiveintegersis40andthe127038.htmltheaveragearithmeticmeanofthe5positiveintegersk107059.htmlacertaincitywithpopulationof132000istobedivided76217.htmlfivepeicesofwoodhaveanaveragelengthof124inchesand123513.htmlthreeboxesofsupplieshaveanaveragearithmeticmean105819.htmlasetof25differentintegershasamedianof50anda129345.htmlthreepeopleeachtook5testsiftherangesoftheirscore127935.htmleachseniorinacollegecoursewroteathesisthelengths126964.htmlinacertainsetoffivenumbersthemedianis128514.htmlshaggyhastolearnthesame71hiraganacharactersand126948.htmlOther min/max questions:PS: search.php?search_id=tag&tag_id=63DS: search.php?search_id=tag&tag_id=42Hope it helps.
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Re: Set R contains five numbers that have an average value of 55 [#permalink]
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Thanks alot Bunuel..now i got that .. i think in REAL GMAT these type of question cum frequenlty..!!.
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Re: Set R contains five numbers that have an average value of 55 [#permalink]
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24 Jan 2013, 03:38
Hi , Here's how I did.. smallest no: s largest no: 3s+20 since mean = median, thought that numbers are in AP. so average= (last no+first no)/2 therefore 55=(s+3s+20)/2 => s=22.5 now l=20+3s => l=87.25 range =ls=65.. Please let me know where I am going wrong.
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Re: Set R contains five numbers that have an average value of 55 [#permalink]
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Sachin9 wrote: Hi ,
Here's how I did..
smallest no: s largest no: 3s+20
since mean = median,
thought that numbers are in AP.
so average= (last no+first no)/2
therefore 55=(s+3s+20)/2 => s=22.5
now l=20+3s => l=87.25
range =ls=65.. Please let me know where I am going wrong. Sachin, you assumed that the numbers are in AP, but problem doesn't state that. This set S = {29, 29, 55, 55, 107} has the maximum range i.e. 78 and mean/median 55. Note that these numbers are not in AP/sequence. Hence you cannot take average of last & first to find the mean.
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Re: Set R contains five numbers that have an average value of 55 [#permalink]
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24 Jan 2013, 17:22
PraPon wrote: Sachin9 wrote: Hi ,
Here's how I did..
smallest no: s largest no: 3s+20
since mean = median,
thought that numbers are in AP.
so average= (last no+first no)/2
therefore 55=(s+3s+20)/2 => s=22.5
now l=20+3s => l=87.25
range =ls=65.. Please let me know where I am going wrong. Sachin, you assumed that the numbers are in AP, but problem doesn't state that. This set S = {29, 29, 55, 55, 107} has the maximum range i.e. 78 and mean/median 55. Note that these numbers are not in AP/sequence. Hence you cannot take average of last & first to find the mean. Thanks mate.. I thought that the numbers would be in AP since their median and mean were same. I now understand that if the nos are in AP , then their median and mean will be same but the vice versa is not necessarily true.
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Re: Largest possible range in Set R [#permalink]
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26 May 2014, 13:17
Bunuel wrote: Orange08 wrote: Set R contains five numbers that have an average value of 55. If the median of the set is equal to the mean, and the largest number in the set is equal to 20 more than three times the smallest number, what is the largest possible range for the numbers in the set?
78 77 1/5 66 1/7 55 1/7 52 {\(a_1\), \(a_2\), \(a_3\), \(a_4\), \(a_5\)} As mean of 5 numbers is 55 then the sum of these numbers is \(5*55=275\); The median of the set is equal to the mean > \(mean=median=a_3=55\); The largest number in the set is equal to 20 more than three times the smallest number > \(a_5=3a_1+20\). So our set is {\(a_1\), \(a_2\), \(55\), \(a_4\), \(3a_1+20\)} and \(a_1+a_2+55+a_4+3a_1+20=275\). The range of a set is the difference between the largest and smallest elements of a set.\(Range=a_5a_1=3a_1+20a_1=2a_1+20\) > so to maximize the range we should maximize the value of \(a_1\) and to maximize \(a_1\) we should minimize all other terms so \(a_2\) and \(a_4\). Min possible value of \(a_2\) is \(a_1\) and min possible value of \(a_4\) is \(median=a_3=55\) > set becomes: {\(a_1\), \(a_1\), \(55\), \(55\), \(3a_1+20\)} > \(a_1+a_1+55+55+3a_1+20=275\) > \(a_1=29\) > \(Range=2a_1+20=78\) Answer: A. Hi Bunuel, Since the statement says that the median = mean, aren't we supposed to assume that it's an evenly spaced set? If so, wouldn't a2 and a4 be different from a1 and a3?




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