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# sets31 Q36

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Manager
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04 Nov 2007, 00:30
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

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Intern
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04 Nov 2007, 00:37
You get the equation

10x + 20 y = k (x+y)

Solve by substitution.
I started with 15
I got x = y but Y>x
then 18, y = 4 x => correct

then 30, y = -2 x = > wrong

Balvinder wrote:
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04 Nov 2007, 06:20
It is D = 18

10x + 20y = kx +ky

For x<y to be true k can take values from 16 to 19.
04 Nov 2007, 06:20
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