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Seven family members are seated around their circular dinner

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VP
Joined: 13 Jun 2004
Posts: 1111

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Location: London, UK
Schools: Tuck'08
Seven family members are seated around their circular dinner [#permalink]

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07 Sep 2004, 17:29
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Seven family members are seated around their circular dinner table. If only the only arrangements that are considered distinct are those where family members are seated in different locations relative to each other, then how many distinct arrangements around the table are possible?
(A) 7
(ÃŸ) 42
(C) 294
(D) 720
(E) 5040

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Manager
Joined: 05 Sep 2004
Posts: 97

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07 Sep 2004, 19:28
Fix one person and rearrange the others = 6! = 720. D.

Hope that's what the question is asking for.

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GMAT Club Legend
Joined: 15 Dec 2003
Posts: 4284

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07 Sep 2004, 19:38
Quote:
If only the only arrangements that are considered distinct are those where family members are seated in different locations relative to each other

Above statement is kinda obvious since we are looking for circular arrangements. It is (n-1)! = 6! = 720
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Best Regards,

Paul

Kudos [?]: 537 [0], given: 0

VP
Joined: 13 Jun 2004
Posts: 1111

Kudos [?]: 51 [0], given: 0

Location: London, UK
Schools: Tuck'08

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07 Sep 2004, 22:52
I agree the question is a little weird...
anyway, you got it right. OA is D.

You both are great GMAT snipers

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07 Sep 2004, 22:52
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Seven family members are seated around their circular dinner

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