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# Seven workers from the first group have to pan out 100 tons

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Eternal Intern
Joined: 07 Jun 2003
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Seven workers from the first group have to pan out 100 tons [#permalink]

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15 Jul 2003, 18:23
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Seven workers from the first group have to pan out 100 tons of auriferous ore. The second group consists of four workers, two apprentices, and one master who work 1/3 and 1┬╜ as fast as does a worker accordingly. The second group has to pan out the same pile of ore. Find a ratio of the time that the first group needs to have the work done to the time that the second group needs.

Is Work Done= 100 piles of ore?

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GMAT Instructor
Joined: 07 Jul 2003
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Schools: Haas, MFE; Anderson, MBA; USC, MSEE

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15 Jul 2003, 23:22
Curly05 wrote:
Seven workers from the first group have to pan out 100 tons of auriferous ore. The second group consists of four workers, two apprentices, and one master who work 1/3 and 1┬╜ as fast as does a worker accordingly. The second group has to pan out the same pile of ore. Find a ratio of the time that the first group needs to have the work done to the time that the second group needs.

Is Work Done= 100 piles of ore?

[I believe the ratio will be 1:2 (the second group will take twice as long as the first group to do the same job). If you are clever, you should be able to solve this in your head.] Cancel - I had a mind fart. Answer should be 37:42.
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AkamaiBrah
Former Senior Instructor, Manhattan GMAT and VeritasPrep
Vice President, Midtown NYC Investment Bank, Structured Finance IT
MFE, Haas School of Business, UC Berkeley, Class of 2005
MBA, Anderson School of Management, UCLA, Class of 1993

Last edited by AkamaiBrah on 15 Jul 2003, 23:51, edited 1 time in total.

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SVP
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15 Jul 2003, 23:36
R is a rate of a "standard" worker.
R/3 is that of an apprentice
3R/2 is that of a master

Work=Rate*Time

the first group) 100=7Rt, where t is the time they need
the second group) 100=(4R+2/3R+3/2R)T, where T is the time they need

t/T= (4R+2/3R+3/2R)/7R=37/42

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GMAT Instructor
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15 Jul 2003, 23:50
AkamaiBrah wrote:
Curly05 wrote:
Seven workers from the first group have to pan out 100 tons of auriferous ore. The second group consists of four workers, two apprentices, and one master who work 1/3 and 1┬╜ as fast as does a worker accordingly. The second group has to pan out the same pile of ore. Find a ratio of the time that the first group needs to have the work done to the time that the second group needs.

Is Work Done= 100 piles of ore?

I believe the ratio will be 1:2 (the second group will take twice as long as the first group to do the same job). If you are clever, you should be able to solve this in your head.

Oops, my bad. I misread the problem to read that there were 4 total workers, of which 2 were apprentices and 1 was a master.

I agree with Stolyar's ratio: 37:42
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AkamaiBrah
Former Senior Instructor, Manhattan GMAT and VeritasPrep
Vice President, Midtown NYC Investment Bank, Structured Finance IT
MFE, Haas School of Business, UC Berkeley, Class of 2005
MBA, Anderson School of Management, UCLA, Class of 1993

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Manager
Joined: 08 Apr 2003
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16 Jul 2003, 03:09
same here...

37:42.

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16 Jul 2003, 03:09
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