Relative distance between both ships when ship B departs the dock= 2*10=20 miles
Relative speed of ship B with respect to ship A= 14-10= 4mph
Time taken by ship B to catch up ship A= 20/4=5 hours
whollymoses wrote:
Ship A departs dock X and heads towards dock Y at a constant speed of 10 miles per hour. 2 later, ship B departs dock X and travels along the same route at a constant speed of 14 miles per hour. Ship A does not reach dock Y before ship B. How many hours will it take for ship B to catch up with ship A?
A. 3 hrs
B. 3.5 hrs
C. 4 hrs
D. 4.5 hrs
E. 5 hrs