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# Simple Geometry Problem GMAT Prep

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Intern
Joined: 09 Jan 2009
Posts: 7
Simple Geometry Problem GMAT Prep [#permalink]

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14 Jan 2009, 03:18
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

can someone give me an explanantion? Don't get it
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VP
Joined: 18 May 2008
Posts: 1260
Re: Simple Geometry Problem GMAT Prep [#permalink]

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14 Jan 2009, 09:37
since angles are same, so the triangles are similar. for similar triangles, the ratio of areas= square of the ratio of similar sides. So if the areas r in ratio 2:1, then the sides are in ratio sqrt(2):1.
Hence C
SVP
Joined: 29 Aug 2007
Posts: 2473
Re: Simple Geometry Problem GMAT Prep [#permalink]

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16 Jan 2009, 14:03
base of the small triangle = s
base of the large triangle = S

height of the small triangle = h
height of the large triangle = H

since corrosponding angtles are equal, the traingles are similar. so ---->
s/S = h/H
Hs= hS
H = hS/s

area of the small triangle = a = 1/2 (hs)
area of the large triangle = 1/2 (HS)

area of the large triangle = 2 (area of the small triangle)
1/2 (HS) = 2 [1/2 (hs)]
(hS/s)(S) = 2hs
S^2 = 2s^2
S = s(sqrt2) or sqrt2(s)
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Intern
Joined: 16 Jan 2009
Posts: 14
Re: Simple Geometry Problem GMAT Prep [#permalink]

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17 Jan 2009, 19:50
Let the height of small triangle be h and the second triangle be H.
Given two triangles are similar ...so the sides are proportional
so

S/s = H/h
Sh/s = H

Given area of the second triangle is twice the area of the first triangle

1/2 S H = 2 . 1/2 . s h

!/2 SH = sh

plug in H as Sh/s

1/2 S. Sh/s = sh

1/2 S^2 = s^2

S^2 = 2 s^2

S = sqrt 2 S

Intern
Joined: 16 Jan 2009
Posts: 14
Re: Simple Geometry Problem GMAT Prep [#permalink]

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17 Jan 2009, 19:51
Let the height of small triangle be h and the second triangle be H.
Given two triangles are similar ...so the sides are proportional
so

S/s = H/h
Sh/s = H

Given area of the second triangle is twice the area of the first triangle

1/2 S H = 2 . 1/2 . s h

!/2 SH = sh

plug in H as Sh/s

1/2 S. Sh/s = sh

1/2 S^2 = s^2

S^2 = 2 s^2

S = sqrt 2 S

Re: Simple Geometry Problem GMAT Prep   [#permalink] 17 Jan 2009, 19:51
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