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# simple mod

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SVP
Joined: 03 Feb 2003
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08 Jun 2003, 01:29
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

|X-2|=(X-1)/2

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SVP
Joined: 03 Feb 2003
Posts: 1603

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09 Jun 2003, 22:53
tzolkin wrote:
Ans : 3 and 5/3

The answers are correct. There are two ways to solve it. To square both parts and solve a quadratic equation by checking each root, or to open up a modul by separating the initial equation in two cases.

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Intern
Joined: 10 Oct 2005
Posts: 8

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09 Jan 2006, 10:52
Is there an easier way to solve these questions? I'm always scared that I'll miss out on some numbers. I can just place numbers and see but I know its not the right and best way !!!

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VP
Joined: 21 Sep 2003
Posts: 1057

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Location: USA

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09 Jan 2006, 11:35
vizzz wrote:
Is there an easier way to solve these questions? I'm always scared that I'll miss out on some numbers. I can just place numbers and see but I know its not the right and best way !!!

vizz,

When we say lxl = 3 it implies that x = 3 or x = -3.

http://www.purplemath.com/modules/absolute.htm

so |x-2| = (x-1)/2 implies
x-2 = (x-1)/2 or x-2 = -(x-1)/2

Solve these two eqns and you should arrive at
x = 3 or x = 5/3
_________________

"To dream anything that you want to dream, that is the beauty of the human mind. To do anything that you want to do, that is the strength of the human will. To trust yourself, to test your limits, that is the courage to succeed."

- Bernard Edmonds

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CEO
Joined: 20 Nov 2005
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Schools: Completed at SAID BUSINESS SCHOOL, OXFORD - Class of 2008

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09 Jan 2006, 14:18
There are two cases

1. x-2 = (x-1)/2 which yields x = 3

2. -(x-2) = (x-1)/2 which yields x = 5/3
_________________

SAID BUSINESS SCHOOL, OXFORD - MBA CLASS OF 2008

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VP
Joined: 20 Sep 2005
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09 Jan 2006, 14:28
3 and 5/3 as above. Expl. same as above.

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Director
Joined: 04 Oct 2005
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Location: Chicago

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09 Jan 2006, 22:45
For positive X => x-2=(x-1)/2=> x=3
For negative X=> -(x-2)=(x-1)/2=>x=5/3

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09 Jan 2006, 22:45
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# simple mod

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