It is currently 17 Nov 2017, 19:43

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# Simple Q

Author Message
Senior Manager
Joined: 24 Jul 2009
Posts: 287

Kudos [?]: 171 [0], given: 0

### Show Tags

15 May 2010, 11:50
00:00

Difficulty:

(N/A)

Question Stats:

67% (00:53) correct 33% (00:41) wrong based on 1 sessions

### HideShow timer Statistics

The average of 4 different positive integers is 125. If the largest of these integers is 150, what is the least possible value of the smallest integer?

* 1
* 2
* 12
* 53
* 100

Kudos [?]: 171 [0], given: 0

Manager
Joined: 20 Apr 2010
Posts: 151

Kudos [?]: 19 [0], given: 16

Location: I N D I A

### Show Tags

17 May 2010, 01:36
i also think the ans is D... whats OA..?

Kudos [?]: 19 [0], given: 16

Senior Manager
Joined: 25 Jun 2009
Posts: 298

Kudos [?]: 151 [0], given: 6

### Show Tags

17 May 2010, 02:45
nverma wrote:
The average of 4 different positive integers is 125. If the largest of these integers is 150, what is the least possible value of the smallest integer?

* 1
* 2
* 12
* 53
* 100

D,

Let the numbers be a,b,c and d

then $$\frac{a+b+c+d}{4}$$ $$= 125$$

a+ b+c +d = 500

d = 150

a+b+c= 350

now 150 is the largest among the lot, then let c= 149 and b = 148 then equation becomes

a+ 148+ 149 = 350 or a = 53

Kudos [?]: 151 [0], given: 6

Manager
Joined: 29 Oct 2009
Posts: 64

Kudos [?]: 3 [0], given: 3

### Show Tags

17 May 2010, 02:46
D should be the ans...

Lets take other numbers to be 148 and 146. Adding these 2 numbers to 150 and then subtracting with 125*4 , ans comes to 56, so only D is closest to that.

Kudos [?]: 3 [0], given: 3

Manager
Joined: 16 Feb 2010
Posts: 179

Kudos [?]: 34 [0], given: 17

### Show Tags

17 May 2010, 07:59
another way to solve
in order to minimize one no we have to maximize all the other no.s to get the same average , the max. no. is 150 so the maximum limit of other no.s is 149 & 148
NOW (148 +149+150 +X)/4 = 125 so x=53 ans option D

Kudos [?]: 34 [0], given: 17

Re: Simple Q   [#permalink] 17 May 2010, 07:59
Display posts from previous: Sort by