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Simple Square Roots Question

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Intern
Joined: 25 Aug 2011
Posts: 7

Kudos [?]: 2 [0], given: 3

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25 Aug 2012, 15:31
I am trying to understand an MGMAT answer explanation (guide 3 chapter 4 question 9 of fourth edition for those who have the book) which I think should be fairly simple but I'm having a brain freeze at the moment.

Can someone please explain how (1)/(square root of 2) = (square root of 2) / (2) ?? I am just having trouble trying to visualize the steps they left out.

Apologies for the sloppy nomenclature. I am still trying to figure out the 'square root' buttons.

thanks!

Kudos [?]: 2 [0], given: 3

Senior Manager
Status: Yale! (whipped and bound)
Joined: 02 May 2012
Posts: 406

Kudos [?]: 149 [0], given: 78

Location: United States (CA)
Concentration: Nonprofit
GMAT 1: 730 Q48 V42
GPA: 3.41
Re: Simple Square Roots Question [#permalink]

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25 Aug 2012, 16:24
I am trying to understand an MGMAT answer explanation (guide 3 chapter 4 question 9 of fourth edition for those who have the book) which I think should be fairly simple but I'm having a brain freeze at the moment.

Can someone please explain how (1)/(square root of 2) = (square root of 2) / (2) ?? I am just having trouble trying to visualize the steps they left out.

Apologies for the sloppy nomenclature. I am still trying to figure out the 'square root' buttons.

thanks!

multiply by 1 (square root 2 / square root 2)
numerator: 1 * square root 2 = square root 2
denominator: square root 2 * square root 2 = 2
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Yale School of Management MBA Candidate, 2015.

Kudos [?]: 149 [0], given: 78

Manager
Joined: 24 Jul 2011
Posts: 75

Kudos [?]: 155 [0], given: 5

Location: India
Concentration: Strategy, General Management
GMAT 1: 670 Q49 V33
WE: Asset Management (Manufacturing)
Re: Simple Square Roots Question [#permalink]

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26 Aug 2012, 07:09
Can someone please explain how (1)/(square root of 2) = (square root of 2) / (2) ?? I am just having trouble trying to visualize the steps they left out.

thanks!

$$1/ \sqrt{2}$$

$$= 1 * \sqrt{2} / \sqrt{2} *\sqrt{2}$$ ( multiplying both numerator and denominator with $$\sqrt{2}$$

$$= \sqrt{2} / 2$$

By the way, this is very basic concept. Hope you're not kidding.
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Kudos [?]: 155 [0], given: 5

Re: Simple Square Roots Question   [#permalink] 26 Aug 2012, 07:09
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