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Six mobsters have arrived at the theater for the premiere of

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Manager
Manager
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Joined: 06 Oct 2009
Posts: 104

Kudos [?]: 180 [0], given: 4

Location: Mexico
Concentration: Entrepreneurship, Finance
GPA: 3.85
WE: Sales (Commercial Banking)
Re: Arrangements(Combinatorics): Six mobsters for Goodbuddies [#permalink]

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New post 03 Oct 2011, 18:32
This is the way I could see the solution clearer:

Total arrangements of 6 mobsters 6! = 760

If we picture all the possible arrangements of lines we will get a rectangle 6 X 120 = 720

J F 1 2 3 4
J 1 F 2 3 4
J 1 2 F 3 4
J 1 2 3 F 4
J 1 2 3 4 F

1 J F 2 3 4
1 J 2 F 3 4

And so on, we will realize that the arrangements will follow a path similar to

1 1 1 1 1
0 1 1 1 1
0 0 1 1 1
0 0 0 1 1
0 0 0 0 1

Clearly half of the total arrangements or 360. Hope it can help some of you!!

Regards

Last edited by Bull78 on 05 Oct 2011, 22:24, edited 1 time in total.

Kudos [?]: 180 [0], given: 4

Intern
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Joined: 26 May 2011
Posts: 19

Kudos [?]: 58 [0], given: 0

Location: United States
Re: PS: Combinatorics [#permalink]

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New post 03 Oct 2011, 19:04
walker wrote:
another way:

the total number of options: \(P^6_6=6!=720\)
All options are divided by two symmetry possibilities: Frankie behind Joey or Joey behind Frankie
Therefore, \(N=\frac{720}{2}=360\)


Considering all the options(6!) there can be only two ways Frankie and Joey can be: Frankie behind Joey or Joey behind Frankie. To get one possibility divide by 2.
Hope this

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Manager
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Joined: 10 Oct 2011
Posts: 119

Kudos [?]: 73 [0], given: 7

Location: India
Concentration: Technology, Entrepreneurship
GMAT 1: 760 Q50 V42
GPA: 3
Re: Arrangements(Combinatorics): Six mobsters for Goodbuddies [#permalink]

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New post 12 Oct 2011, 14:12
The questions says that frank is behind george, that in no way means they are together, next to each other.

the cases would be :-


1. G||||| : F could be anywhere behind G, so 5! ways +
2.XG|||| : F could be any one of |, so 4* 4! ways +
3.XXG||| : F could be any one of |, so 4*3*3! ways
4.XXXG|| : F could be any one of |, so 4*3*2*2! ways
5.XXXXG| : F could be just |, so 4*3*2*1*1! ways


adding 1,2,3,4,5, it comesa to 120+96+72+48+24 = 360. answer option D.
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Kudos [?]: 73 [0], given: 7

Re: Arrangements(Combinatorics): Six mobsters for Goodbuddies   [#permalink] 12 Oct 2011, 14:12

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