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Sixty percent of the members of a study group are women, and

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Sixty percent of the members of a study group are women, and  [#permalink]

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New post 10 Dec 2012, 09:44
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Sixty percent of the members of a study group are women, and 45 percent of those women are lawyers. If one member of the study group is to be selected at random, what is the probability that the member selected is a woman lawyer?

(A) 0.10
(B) 0.15
(C) 0.27
(D) 0.33
(E) 0.45
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Re: Sixty percent of the members of a study group are women, and  [#permalink]

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New post 10 Dec 2012, 09:47
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Walkabout wrote:
Sixty percent of the members of a study group are women, and 45 percent of those women are lawyers. If one member of the study group is to be selected at random, what is the probability that the member selected is a woman lawyer?

(A) 0.10
(B) 0.15
(C) 0.27
(D) 0.33
(E) 0.45


Say there are 100 people in that group, then there would be 0.6*0.45*100=27 women lawyers, which means that the probability that the member selected is a woman lawyer is favorable/total=27/100.

Answer: C.
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Re: Sixty percent of the members of a study group are women, and  [#permalink]

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New post 25 Apr 2014, 22:40
Result = 0.6*0/45=0.27
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Re: Sixty percent of the members of a study group are women, and  [#permalink]

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New post 10 Jun 2016, 10:33
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Walkabout wrote:
Sixty percent of the members of a study group are women, and 45 percent of those women are lawyers. If one member of the study group is to be selected at random, what is the probability that the member selected is a woman lawyer?

(A) 0.10
(B) 0.15
(C) 0.27
(D) 0.33
(E) 0.45


This is a two-part probability question. We should first notice that since our answer choices are in decimal form, we can use a real numerical value for the total number of members of the study group. A convenient number to use is 100.

We are first told that 60 percent of the members in the group are women. Thus we can say:

0.6 x 100 = 60 women

We are next told that 45 percent of these 60 women are lawyers. We can then say:

0.45 x 60 = 27 women lawyers

Finally, we need to determine the probability of selecting a woman lawyer from the group. Since there are 100 total members and 27 of them are women lawyers, the probability is 27/100 = 0.27.

Answer C.
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Re: Sixty percent of the members of a study group are women, and  [#permalink]

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New post 16 Jun 2016, 07:26
0.6*0.45 =(6/10) * (45/100) = 27/100 =0.27
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Re: Sixty percent of the members of a study group are women, and  [#permalink]

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New post 25 Mar 2017, 05:21
let's try smart numbers, there are 100 people in the group
600 of the people are women, 27 are lawyers, 27/100=0,27
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Re: Sixty percent of the members of a study group are women, and  [#permalink]

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New post 13 Apr 2018, 08:58
Why is this questions labaled as a HARD on at OG2018?
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Re: Sixty percent of the members of a study group are women, and  [#permalink]

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New post 28 Jan 2019, 12:12
Walkabout wrote:
Sixty percent of the members of a study group are women, and 45 percent of those women are lawyers. If one member of the study group is to be selected at random, what is the probability that the member selected is a woman lawyer?

(A) 0.10
(B) 0.15
(C) 0.27
(D) 0.33
(E) 0.45



Because we're working with percentages, using 100 people as the total makes things easier. Also,

Total Number of People: 100

60% of those people are women: 100 * \(\frac{6}{10}\) (Converting and reducing those percentages into fractions makes it easier to calculate quickly)

45% of those women are lawyers: 100 * \(\frac{6}{10}\) * \(\frac{45}{100}\)

100 * \(\frac{3}{5}\) * \(\frac{3}{20}\) = 27 people who are women and lawyers

27/100 = 27%

Answer is C
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Sixty percent of the members of a study group are women, and  [#permalink]

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New post 14 Apr 2020, 19:49
Quote:
Sixty percent of the members of a study group are women, and 45 percent of those women are lawyers. If one member of the study group is to be selected at random, what is the probability that the member selected is a woman lawyer?

(A) 0.10
(B) 0.15
(C) 0.27
(D) 0.33
(E) 0.45

Let,
Total 100
women=60% of 100=60. Lawyer=45% of 60=27.
So, probability 27/100=0.27.
Correct answer
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Re: Sixty percent of the members of a study group are women, and  [#permalink]

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New post 14 Apr 2020, 21:16
Let total number of members of the study group be 'X'.

Probability (woman lawyer)= [number of women lawyers] / [total number of members of study group]

Here, number of women lawyers= 45% of 60% of X = 0.45 x 0.60 x X = 0.27 X

Substituting the value in above equation,
Probability = 0.27X / X = 0.27

Answer (C)


Walkabout wrote:
Sixty percent of the members of a study group are women, and 45 percent of those women are lawyers. If one member of the study group is to be selected at random, what is the probability that the member selected is a woman lawyer?

(A) 0.10
(B) 0.15
(C) 0.27
(D) 0.33
(E) 0.45

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Re: Sixty percent of the members of a study group are women, and  [#permalink]

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New post 16 Apr 2020, 09:34
let, there are 100 people in that group.
60 percent of the members in the group are women
so, women =0.6 x 100 = 60
45 percent of these 60 women are lawyers.
so, women lawyers =0.45 x 60 = 27
the probability that the member selected is a woman lawyer = 27/100 =.27

correct answer C
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Re: Sixty percent of the members of a study group are women, and   [#permalink] 16 Apr 2020, 09:34

Sixty percent of the members of a study group are women, and

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