Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 500,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

Solutions x, y and z are mixed at a ratio of 5:7:9 [#permalink]

Show Tags

29 May 2006, 06:10

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Solutions x, y and z are mixed at a ratio of 5:7:9 respectively in order to formulate one batch of 273 gallons of Brand X cleaning fluid. If the supplier of the solutions mixed up the order and supplied 20 gallons less of solution x, 28 gallons more of solution y and 54 gallons less of solution z, how many gallons of Brand X could be made?

Hallo raaja,
We need 273 gallons of brand X. Then brand X will contain 273/21=13 gallons of each part multiplied b y the respective ratio. Or x-65, y-91,z-117. When we take into account the confusion of the supplier, we have x 45,y-119, z-63. If we take z=9*7 then we need of each component 7 gallons or x-35,y-49, z-63 and the mixture would be 147 gallons in total

Hallo raaja, We need 273 gallons of brand X. Then brand X will contain 273/21=13 gallons of each part multiplied b y the respective ratio. Or x-65, y-91,z-117. When we take into account the confusion of the supplier, we have x 45,y-119, z-63. If we take z=9*7 then we need of each component 7 gallons or x-35,y-49, z-63 and the mixture would be 147 gallons in total

I got E too, using the same approach. However, I made a couple silly errors along the way, glossing over the line that 28 gallons MORE of solution y was supplied.

Shows I gotta be more careful when reading to avoid silly mistakes.

Solutions x, y and z are mixed at a ratio of 5:7:9 respectively in order to formulate one batch of 273 gallons of Brand X cleaning fluid. If the supplier of the solutions mixed up the order and supplied 20 gallons less of solution x, 28 gallons more of solution y and 54 gallons less of solution z, how many gallons of Brand X could be made?

a) 231 b) 189 c) 158 d) 156 e) 147

= [{(273/21)(9) - 54}/9]21= 147

consider z cuz it is supplied by large reduction. therefore, the qty of z determines the qty of X.

if y were greately reduced, then it would be taken for the calculation.

Now, this is the point where you need to figure out, which one should be the limiting quantity. Thankfully, it's pretty easy in this case as z is the one that limits the other two.

Thus, if z=63, one part = 63/9 = 7 litres.
x= 5*7 = 35 litres, and y= 7*7 = 49 litres.