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Some of the people in Town X are left-handed, some are tall

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Bullet
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Some of the people in Town X are left-handed, some are tall [#permalink] New post   05 Dec 2009, 10:27
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Some of the people in Town X are left-handed, some are tall, some are both, and some are neither. In Town Y, three times as many people are left-handed > as are left-handed in Town X, three times as many people are tall as are tall in Town X, three times as many people are both as are both in Town X, but no one is neither. If the total number of people in Town X is four times greater than the total number of people in Town Y, which of the following could be the number of people in Town X who are neither left-handed nor tall?

(A) 23
(B) 39
(C) 72
(D) 143
(E) 199
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D
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Bunuel
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Re: Some of the people in Town X are left-handed, some are tall [#permalink] New post   24 Feb 2012, 15:39
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Bullet wrote:
Some of the people in Town X are left-handed, some are tall, some are both, and some are neither. In Town Y, three times as many people are left-handed > as are left-handed in Town X, three times as many people are tall as are tall in Town X, three times as many people are both as are both in Town X, but no one is neither. If the total number of people in Town X is four times greater than the total number of people in Town Y, which of the following could be the number of people in Town X who are neither left-handed nor tall?

(A) 23
(B) 39
(C) 72
(D) 143
(E) 199

Show Spoiler
I calculated OA and it looks like D but i'm not 100% sure


Yes, correct answer is indeed D.

Given:
{X}={Left} + {Tall} - {Both} + {Neither};

{Y} = 3*{Left} + 3*{Tall} - 3*{Both};

Since the total number of people in Town X is four times greater than the total number of people in Town Y, then:
{Left} + {Tall} - {Both} + {Neither}=4*(3*{Left} + 3*{Tall} - 3*{Both});

{Neither}=11*({Left} + {Tall} - {Both}), which means that # of people in Town X who are neither left-handed nor tall must be a multiple of 11.

Only answer choice D, is a multiple of 11: 143=11*13.

Answer: D.
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Re: Overlapping Sets Problem [#permalink] New post   05 Dec 2009, 10:32
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Let A = Left Handed, B = Tall and C = Both of left handed and Tall, D= neither

Two overlapping sets problem, therefore

Total = G1+ G2 - Both + neither

Town X
total = A+B+C+D

Town Y
= 3A+3B+3C + 0

as Town X 4 times greater.
4(3A+3B+3C) = A+B+C+D
after simplifying D = 11(A+B+C)

as D is the only multiple of 11 so to me it look like an answer.

Comments please
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Re: Overlapping Sets Problem [#permalink] New post   24 Feb 2012, 15:22
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Bullet wrote:
as Town X 4 times greater.
4(3A+3B+3C) = A+B+C+D
after simplifying D = 11(A+B+C)


12(A+B+C) = A+B+C+D
look at both sides now. you have 12 times A rather than 3 times A.
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Re: Some of the people in Town X are left-handed, some are tall [#permalink] New post   17 Apr 2015, 00:44
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earnit wrote:
Bunuel wrote:
Bullet wrote:
Some of the people in Town X are left-handed, some are tall, some are both, and some are neither. In Town Y, three times as many people are left-handed > as are left-handed in Town X, three times as many people are tall as are tall in Town X, three times as many people are both as are both in Town X, but no one is neither. If the total number of people in Town X is four times greater than the total number of people in Town Y, which of the following could be the number of people in Town X who are neither left-handed nor tall?

(A) 23
(B) 39
(C) 72
(D) 143
(E) 199

Show Spoiler
I calculated OA and it looks like D but i'm not 100% sure


Yes, correct answer is indeed D.

Given:
{X}={Left} + {Tall} - {Both} + {Neither};

{Y} = 3*{Left} + 3*{Tall} - 3*{Both};

Since the total number of people in Town X is four times greater than the total number of people in Town Y, then:
{Left} + {Tall} - {Both} + {Neither}=4*(3*{Left} + 3*{Tall} - 3*{Both});

{Neither}=11*({Left} + {Tall} - {Both}), which means that # of people in Town X who are neither left-handed nor tall must be a multiple of 11.

Only answer choice D, is a multiple of 11: 143=11*13.

Answer: D.



I think the highlighted portion actually means: If X is the total population of Town X and Y is the total population of town Y then
X = 4Y + Y = 5Y
The Question stem states 4 times greater than Y not 4 times as much as Y.

Kindly Let me know if at all i am wrong.


This discussion has taken place many times before. Check out this link to understand why it will be the way Bunuel has done it: https://mathforum.org/library/drmath/view/52334.html
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Re: Some of the people in Town X are left-handed, some are tall [#permalink] New post   24 Sep 2019, 19:40
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JonShukhrat wrote:
Bullet wrote:
Some of the people in Town X are left-handed, some are tall, some are both, and some are neither. In Town Y, three times as many people are left-handed > as are left-handed in Town X, three times as many people are tall as are tall in Town X, three times as many people are both as are both in Town X, but no one is neither. If the total number of people in Town X is four times greater than the total number of people in Town Y, which of the following could be the number of people in Town X who are neither left-handed nor tall?

(A) 23
(B) 39
(C) 72
(D) 143
(E) 199


Hi MartyTargetTestPrep,

Could you, please, shed some light on the interpretation of the above highlighted part of the stem?

Does it mean 4x or 5x on GMAT?

Many thanks in advance.

Ideally, it would mean 5x, but I'm not sure that every writer would agree with that interpretation.

Fortunately, I am pretty sure that such an unclear way of expressing such a relationship would not be used in an official GMAT quant question, though wording like that has appeared in the correct answer to an official Sentence Correction question.
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Re: Some of the people in Town X are left-handed, some are tall [#permalink] New post   25 Oct 2021, 07:52
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sam12rawat wrote:
Bunuel wrote:
Bullet wrote:
Some of the people in Town X are left-handed, some are tall, some are both, and some are neither. In Town Y, three times as many people are left-handed > as are left-handed in Town X, three times as many people are tall as are tall in Town X, three times as many people are both as are both in Town X, but no one is neither. If the total number of people in Town X is four times greater than the total number of people in Town Y, which of the following could be the number of people in Town X who are neither left-handed nor tall?

(A) 23
(B) 39
(C) 72
(D) 143
(E) 199

Show Spoiler
I calculated OA and it looks like D but i'm not 100% sure


Yes, correct answer is indeed D.

Given:
{X}={Left} + {Tall} - {Both} + {Neither};

{Y} = 3*{Left} + 3*{Tall} - 3*{Both};

Since the total number of people in Town X is four times greater than the total number of people in Town Y, then:
{Left} + {Tall} - {Both} + {Neither}=4*(3*{Left} + 3*{Tall} - 3*{Both});

{Neither}=11*({Left} + {Tall} - {Both}), which means that # of people in Town X who are neither left-handed nor tall must be a multiple of 11.

Only answer choice D, is a multiple of 11: 143=11*13.

Answer: D.



Hi Bunuel , Could you please elaborate on why it would be 4 times the population of X and not 5 times?


I think the following posts should clear your doubt:
https://gmatclub.com/forum/tires-r-us-h ... l#p2357023
https://gmatclub.com/forum/every-attend ... l#p2286932
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Re: Some of the people in Town X are left-handed, some are tall [#permalink] New post   13 Jul 2012, 02:08
I am not fine with the language with this question.. does four times greater right usage.. or should it be four times..does the same meaning is construed.
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Re: Some of the people in Town X are left-handed, some are tall [#permalink] New post   01 Mar 2015, 18:55
Hi Bunnel,

I have a quick question. The question says "total number of people in Town X is four times greater than the total number of people in Town Y". Wouldn't this translate to X=5Y instead of X=4Y. Sorry if I am missing something.
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Re: Some of the people in Town X are left-handed, some are tall [#permalink] New post   16 Apr 2015, 19:51
Bunuel wrote:
Bullet wrote:
Some of the people in Town X are left-handed, some are tall, some are both, and some are neither. In Town Y, three times as many people are left-handed > as are left-handed in Town X, three times as many people are tall as are tall in Town X, three times as many people are both as are both in Town X, but no one is neither. If the total number of people in Town X is four times greater than the total number of people in Town Y, which of the following could be the number of people in Town X who are neither left-handed nor tall?

(A) 23
(B) 39
(C) 72
(D) 143
(E) 199

Show Spoiler
I calculated OA and it looks like D but i'm not 100% sure


Yes, correct answer is indeed D.

Given:
{X}={Left} + {Tall} - {Both} + {Neither};

{Y} = 3*{Left} + 3*{Tall} - 3*{Both};

Since the total number of people in Town X is four times greater than the total number of people in Town Y, then:
{Left} + {Tall} - {Both} + {Neither}=4*(3*{Left} + 3*{Tall} - 3*{Both});

{Neither}=11*({Left} + {Tall} - {Both}), which means that # of people in Town X who are neither left-handed nor tall must be a multiple of 11.

Only answer choice D, is a multiple of 11: 143=11*13.

Answer: D.



I think the highlighted portion actually means: If X is the total population of Town X and Y is the total population of town Y then
X = 4Y + Y = 5Y
The Question stem states 4 times greater than Y not 4 times as much as Y.

Kindly Let me know if at all i am wrong.
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Re: Some of the people in Town X are left-handed, some are tall [#permalink] New post   17 Apr 2015, 04:42
w+x+y+z=12w+12x+12y

z=11w+11x+11y

z=11(w+x+z)

it should be multiple of 11

D
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Some of the people in Town X are left-handed, some are tall [#permalink] New post   24 Sep 2019, 13:41
Bullet wrote:
Some of the people in Town X are left-handed, some are tall, some are both, and some are neither. In Town Y, three times as many people are left-handed > as are left-handed in Town X, three times as many people are tall as are tall in Town X, three times as many people are both as are both in Town X, but no one is neither. If the total number of people in Town X is four times greater than the total number of people in Town Y, which of the following could be the number of people in Town X who are neither left-handed nor tall?

(A) 23
(B) 39
(C) 72
(D) 143
(E) 199


Hi MartyTargetTestPrep,

Could you, please, shed some light on the interpretation of the above highlighted part of the stem?

Does it mean 4x or 5x on GMAT?

Many thanks in advance.
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Re: Some of the people in Town X are left-handed, some are tall [#permalink] New post   25 Sep 2019, 02:22
MartyTargetTestPrep wrote:
JonShukhrat wrote:
Bullet wrote:
Some of the people in Town X are left-handed, some are tall, some are both, and some are neither. In Town Y, three times as many people are left-handed > as are left-handed in Town X, three times as many people are tall as are tall in Town X, three times as many people are both as are both in Town X, but no one is neither. If the total number of people in Town X is four times greater than the total number of people in Town Y, which of the following could be the number of people in Town X who are neither left-handed nor tall?

(A) 23
(B) 39
(C) 72
(D) 143
(E) 199


Hi MartyTargetTestPrep,

Could you, please, shed some light on the interpretation of the above highlighted part of the stem?

Does it mean 4x or 5x on GMAT?

Many thanks in advance.

Ideally, it would mean 5x, but I'm not sure that every writer would agree with that interpretation.

Fortunately, I am pretty sure that such an unclear way of expressing such a relationship would not be used in an official GMAT quant question, though wording like that has appeared in the correct answer to an official Sentence Correction question.


Once again many thanks Marty!
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Re: Some of the people in Town X are left-handed, some are tall [#permalink] New post   25 Oct 2021, 04:38
Bunuel wrote:
Bullet wrote:
Some of the people in Town X are left-handed, some are tall, some are both, and some are neither. In Town Y, three times as many people are left-handed > as are left-handed in Town X, three times as many people are tall as are tall in Town X, three times as many people are both as are both in Town X, but no one is neither. If the total number of people in Town X is four times greater than the total number of people in Town Y, which of the following could be the number of people in Town X who are neither left-handed nor tall?

(A) 23
(B) 39
(C) 72
(D) 143
(E) 199

Show Spoiler
I calculated OA and it looks like D but i'm not 100% sure


Yes, correct answer is indeed D.

Given:
{X}={Left} + {Tall} - {Both} + {Neither};

{Y} = 3*{Left} + 3*{Tall} - 3*{Both};

Since the total number of people in Town X is four times greater than the total number of people in Town Y, then:
{Left} + {Tall} - {Both} + {Neither}=4*(3*{Left} + 3*{Tall} - 3*{Both});

{Neither}=11*({Left} + {Tall} - {Both}), which means that # of people in Town X who are neither left-handed nor tall must be a multiple of 11.

Only answer choice D, is a multiple of 11: 143=11*13.

Answer: D.



Hi Bunuel , Could you please elaborate on why it would be 4 times the population of X and not 5 times?
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Re: Some of the people in Town X are left-handed, some are tall [#permalink] New post   19 Mar 2023, 21:07
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