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Source: GMATPrep I would like to understand the concept

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VP
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Source: GMATPrep I would like to understand the concept [#permalink]

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New post 10 Oct 2008, 09:01
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A
B
C
D
E

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Source: GMATPrep

I would like to understand the concept behind this.
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Re: DS : Reminder [#permalink]

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New post 10 Oct 2008, 10:35
(n-1)(n)(n+1) are 3 consecutives ,

24 = 2^3*3

from 1

if n is not dev by 2 thus

n-1, n+1 are even ( 2,3,4) ( 4,5,6) (6,7,8)

8/24 r = 8 , r = 0 , r = 2

from 2

(1,2,3) ( 3,4,5) 0r ( 4,5,6)

r = 4 or 15 or 0 insuff

both together

(4,5,6) and 6,7,8 sutisfies 1,2 however yeild r = 0

C is my answer

Thanks Bruce for the wake up call i owe u one :lol:

Last edited by yezz on 10 Oct 2008, 11:05, edited 2 times in total.

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VP
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Re: DS : Reminder [#permalink]

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New post 10 Oct 2008, 10:47
yezz wrote:
(n-1)(n)(n+1) are 3 consecutives ,

24 = 2^3*3

from 1

if n is not dev by 2 thus

n-1, n+1 are even ( 2,3,4) ( 4,5,6) (6,7,8)

24/24 r = 0 , 120/24 r = 5 , r = 14
from 2

(1,2,3) ( 3,4,5) 0r ( 4,5,6)

r = 7 or 5/2 or 5 insuff

both together

(4,5,6) and 6,7,8 sutisfies 1,2 however yeild different r

E


I think you misread the problem Yezz. There is no "n" in the question.
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Re: DS : Reminder [#permalink]

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New post 10 Oct 2008, 16:09
1
This post received
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(n^2 -1) = 24x + R

1. n is not divisible by 2
N is odd

To satisfy the equation, n should be atleast 5 with R = 0
n = 5 -> R = 0
n = 7 -> R = 0
n = 9 -> R = 8
Not Sufficient

2. n is not divisible by 3
N is not 3,6,9,12...

To satisfy the equation, n should be atleast 5 with R = 0
n = 5 -> R = 0
n = 7 -> R = 0
n = 8 -> R = 15
Not Sufficient

Together:
Intersection of {5,7,9,11,13,15,17...} and {5,7,8,10,11,13,17....}
{5,7,11,13,17......}

With each integer, R = 0

so, answer is C

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VP
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Joined: 30 Jun 2008
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Re: DS : Reminder [#permalink]

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New post 10 Oct 2008, 19:16
LiveStronger wrote:
(n^2 -1) = 24x + R

1. n is not divisible by 2
N is odd

To satisfy the equation, n should be atleast 5 with R = 0
n = 5 -> R = 0
n = 7 -> R = 0
n = 9 -> R = 8
Not Sufficient

2. n is not divisible by 3
N is not 3,6,9,12...

To satisfy the equation, n should be atleast 5 with R = 0
n = 5 -> R = 0
n = 7 -> R = 0
n = 8 -> R = 15
Not Sufficient

Together:
Intersection of {5,7,9,11,13,15,17...} and {5,7,8,10,11,13,17....}
{5,7,11,13,17......}

With each integer, R = 0

so, answer is C


Thank you LiveStronger :) +1 for you
_________________

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Kudos [?]: 707 [0], given: 1

Re: DS : Reminder   [#permalink] 10 Oct 2008, 19:16
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