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# Spokesperson: In the 2006 election of the city mayor, 55% of

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Spokesperson: In the 2006 election of the city mayor, 55% of [#permalink]

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16 May 2008, 07:28
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Question Stats:

69% (01:06) correct 31% (01:14) wrong based on 358 sessions

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Spokesperson: In the 2006 election of the city mayor, 55% of the voters were female. All the voters were between ages 18 and 70 and 2/3 of them supported the incumbent mayor. The incumbent mayor won the election with a substantially greater number of votes than any other candidate.

If the statements made by the Spokesperson are true, then which of the following must be true?
a.At least 1/2 of the female voters supported the incumbent mayor.
b.The incumbent mayor received stronger support from the female voters than from the male voters.
c.There were no other candidates in the election who received more than 30% of all the votes.
d.45% of the voters in the election were male and none of them were 75 years old.
e.If the proportion of male and female voters in the city remains the same, the incumbent mayor is also likely to win the next election.

cheers!
bepositive
[Reveal] Spoiler: OA

Last edited by abhimahna on 15 Oct 2017, 10:27, edited 1 time in total.

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Re: Spokesperson: In the 2006 election of the city mayor, 55% of [#permalink]

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16 May 2008, 07:37
1
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D for me.

bepositive wrote:
Spokesperson: In the 2006 election of the city mayor, 55% of the voters were female. All the voters were between ages 18 and 70 and 2/3 of them supported the incumbent mayor. The incumbent mayor won the election with a substantially greater number of votes than any other candidate.

If the statements made by the Spokesperson are true, then which of the following must be true?
a.At least 1/2 of the female voters supported the incumbent mayor. <-- not necessarily true. If there were 100 voters then 66 voted for mayor. All of the remaining 34 could be female and that means less then 1/2 of females voted for mayor.

b.The incumbent mayor received stronger support from the female voters than from the male voters. <-- Again not necessarily true similar reasoning as A

c.There were no other candidates in the election who received more than 30% of all the votes. <-- We dont know how many candidates there are. There could be just 2 candidates and the other one could have received 34 votes.

d.45% of the voters in the election were male and none of them were 75 years old. <-- bingo if 55% are female, then 45 are male. Since no one is above 70, no ones above 75 either.

e.If the proportion of male and female voters in the city remains the same, the incumbent mayor is also likely to win the next election. <-- rather silly statement if you ask me.

cheers!
bepositive

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Re: Spokesperson: In the 2006 election of the city mayor, 55% of [#permalink]

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16 May 2008, 07:56
thanks dude...

yup it is D..i did question by POE as rest of the choices except make no sense at all...

still can you explain why D is correct----i mean some reason....thanks in advance

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Re: Spokesperson: In the 2006 election of the city mayor, 55% of [#permalink]

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16 May 2008, 08:01
i was sweatin when i read this q ... but quickly and luckily found D

Its the one that you can find support for in the passage very easily ... we are told 55% of voters are women, so 45% must be men ... and we are told ALL voters are btwn 18 and 70, so no one can be 75, male or female.

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Re: Spokesperson: In the 2006 election of the city mayor, 55% of [#permalink]

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16 May 2008, 08:06
Look at my comments next to the answer choices on my last post.

bepositive wrote:
thanks dude...

yup it is D..i did question by POE as rest of the choices except make no sense at all...

still can you explain why D is correct----i mean some reason....thanks in advance

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Re: Spokesperson: In the 2006 election of the city mayor, 55% of [#permalink]

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16 May 2008, 08:22
lesson learnt ..attention to detail.
I never saw '75' in D. I thought (blindly) it was 70 and started searching for answer. Never made it.
Thanks simple but good one.

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Re: Spokesperson: In the 2006 election of the city mayor, 55% of [#permalink]

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16 May 2008, 09:40
true saravalli.....read slowly but don't make it a haste approach...and get this wrong..

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Re: Spokesperson: In the 2006 election of the city mayor, 55% of [#permalink]

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16 May 2008, 09:46
Code:
Wow. Do we have math in verbal..   Good for guys like me.

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Re: Spokesperson: In the 2006 election of the city mayor, 55% of [#permalink]

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28 Aug 2012, 17:03
Is there a faster way to solve CR problems which have numbers/data in it.Or doing the grunt work is the only way forward?

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Re: Spokesperson: In the 2006 election of the city mayor, 55% of [#permalink]

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29 Aug 2012, 12:23
it is clearly d
that is the only option which can be inferred

to be precise that is paraphrased premise in the argument
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Re: Spokesperson: In the 2006 election of the city mayor, 55% of [#permalink]

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01 Sep 2012, 12:04
+1 D

That's why we always take a quick look in all the alternatives before making calculations.
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Re: Spokesperson: In the 2006 election of the city mayor, 55% of [#permalink]

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30 Sep 2013, 06:08
metallicafan wrote:
+1 D

That's why we always take a quick look in all the alternatives before making calculations.

It is a mathematical reasoning not Critical reasoning.

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Re: Spokesperson: In the 2006 election of the city mayor, 55% of [#permalink]

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31 Jul 2014, 23:15
bepositive wrote:
Spokesperson: In the 2006 election of the city mayor, 55% of the voters were female. All the voters were between ages 18 and 70 and 2/3 of them supported the incumbent mayor. The incumbent mayor won the election with a substantially greater number of votes than any other candidate.

If the statements made by the Spokesperson are true, then which of the following must be true?
a.At least 1/2 of the female voters supported the incumbent mayor.
b.The incumbent mayor received stronger support from the female voters than from the male voters.
c.There were no other candidates in the election who received more than 30% of all the votes.
d.45% of the voters in the election were male and none of them were 75 years old.
e.If the proportion of male and female voters in the city remains the same, the incumbent mayor is also likely to win the next election.

cheers!
bepositive

D is the answer. 55% were female --> 45% were male, all voters were b/w 18 & 70 --> none of them were 75
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Re: Spokesperson: In the 2006 election of the city mayor, 55% of [#permalink]

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24 Aug 2016, 22:08
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Re: Spokesperson: In the 2006 election of the city mayor, 55% of [#permalink]

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07 Sep 2016, 09:07
This argument essentially asks us to find a conclusion that must be true based on the facts presented by the spokesperson. When you analyze the answer choices, remember that the correct answer to questions of this type must be the
claim that does not require any additional assumptions.

Since 55% of the voters were female, the remaining 45% were male; also, since all the voters were between ages 18 and 70, no voters, either male or female, could have been 75 years old. This answer choice does not require any additional assumptions and therefore must be true.

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Re: Spokesperson: In the 2006 election of the city mayor, 55% of [#permalink]

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07 Sep 2016, 10:46
bepositive wrote:
Spokesperson: In the 2006 election of the city mayor,55% of the voters were female. All the voters were between ages 18 and 70 and 2/3 of them supported the incumbent mayor. The incumbent mayor won the election with a substantially greater number of votes than any other candidate.

If the statements made by the Spokesperson are true, then which of the following must be true?

a.At least 1/2 of the female voters supported the incumbent mayor.
b.The incumbent mayor received stronger support from the female voters than from the male voters.
c.There were no other candidates in the election who received more than 30% of all the votes.
d.45% of the voters in the election were male and none of them were 75 years old.
e.If the proportion of male and female voters in the city remains the same, the incumbent mayor is also likely to win the next election.

cheers!
bepositive

It's best to solve this question by taking some numbers -

Let No of Voters in the age group of 18 -20 Years be 300
Female Voters is 165
Male Voters is 135

2/3rd of the Voters support the incumbent Mayor, so 200 voters supported the mayor and are likely to vote in favor of him. ( Assuming all eligible voters cast their votes)
So, The Mayor didn't get 1/3rd of the total Votes , ie 100 votes and won the election by a substantially greater number of votes than any other candidate.

We can say the Winner got 66.67% of the total votes and the other candidates got 33.33% of the total votes cast.

Among the options presented (D) directly flows from the stimulus ( Highlighted parts of the stimulus )

1. 55% of the voters were female = 45% of the voters were male
2. All the voters were between ages 18 and 70 = All the voters were less than 75 Years age.

Remember for a must be true type question PowerScore CR states -

 1. Paraphrase / Restate what has already been presented in the stimulus.2. Results from a combination of 2 or More statements presented in the stimulus.

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Re: Spokesperson: In the 2006 election of the city mayor, 55% of   [#permalink] 07 Sep 2016, 10:46
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