It is currently 18 Nov 2017, 09:26

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# Square A is inscribed in circle X. Square B is inscribed in

 new topic post reply Question banks Downloads My Bookmarks Reviews Important topics
Author Message
TAGS:

### Hide Tags

Senior Manager
Affiliations: UWC
Joined: 09 May 2012
Posts: 393

Kudos [?]: 1656 [0], given: 100

GMAT 1: 620 Q42 V33
GMAT 2: 680 Q44 V38
GPA: 3.43
WE: Engineering (Entertainment and Sports)
Square A is inscribed in circle X. Square B is inscribed in [#permalink]

### Show Tags

06 Jun 2012, 03:25
4
This post was
BOOKMARKED
00:00

Difficulty:

25% (medium)

Question Stats:

84% (02:03) correct 16% (02:08) wrong based on 97 sessions

### HideShow timer Statistics

Square A is inscribed in circle X. Square B is inscribed in circle Y. The perimeter of square B is twice the perimeter of square A. The area of circle Y is equal to k multiplied by the area of circle X. What is the value of k ?

A. 2
B. 3
C. 4
D. 6
E. 8
[Reveal] Spoiler: OA

Kudos [?]: 1656 [0], given: 100

Manager
Affiliations: Project Management Professional (PMP)
Joined: 30 Jun 2011
Posts: 197

Kudos [?]: 83 [0], given: 12

Location: New Delhi, India
Re: Square A is inscribed in circle X. Square B is inscribed in [#permalink]

### Show Tags

06 Jun 2012, 04:23
macjas wrote:
Square A is inscribed in circle X. Square B is inscribed in circle Y. The perimeter of square B is twice the perimeter of square A. The area of circle Y is equal to k multiplied by the area of circle X. What is the value of k ?

A. 2
B. 3
C. 4
D. 6
E. 8

If Peri(sqrB)=2 x Per(SqrA)
=> side(sqrB)= 2 x side(SqrA)
=> diagonal(sqrB)= 2 x daigonal(SqrA)
=> Radius of circle B= 2 x Radius of circle B [ as diagonal of square is daimeter of circle]
=> Area of Circle B = 4 x area of cicle a [As area =pie x (radius)^2]
_________________

Best
Vaibhav

If you found my contribution helpful, please click the +1 Kudos button on the left, Thanks

Kudos [?]: 83 [0], given: 12

Intern
Status: Waiting...
Joined: 10 Jan 2012
Posts: 30

Kudos [?]: 10 [0], given: 5

Concentration: Strategy, International Business
Schools: Duke '15 (M)
GMAT 1: 750 Q48 V42
Re: Square A is inscribed in circle X. Square B is inscribed in [#permalink]

### Show Tags

07 Jun 2012, 02:50
1
This post was
BOOKMARKED
Let a = side of square A;
Let b = side of square B;

Perimeter of B = 4b
Perimeter of A = 4a

Perimeter of B = 2 * Perimeter of A
4b = 2 * 4a;
b = 2a;

From Pythagoras rule, length of a diagonal equals \sqrt{2} * side of the square:
Diagonal of square A = $$\sqrt{2} * a$$
Diagonal of square B = $$\sqrt{2} * b = \sqrt{2} * 2a = \sqrt{8} * a$$

Radius of circle X = Half of Diagonal of square A, since square A is inscribed in circle X = $$\sqrt{2} * a/2;$$
Radius of circle Y = Half of Diagonal of square B, since square B is inscribed in circle Y =$$\sqrt{8} * a/2;$$

Area of circle X = $$Pi * r^2 = Pi * (\sqrt{2} * a/2)^2 = Pi * a/2;$$
Area of circle Y = $$Pi * r^2 = Pi * (\sqrt{8} * a/2)^2 = Pi * 2a;$$

Area of circle Y = $$k *$$Area of circle X
$$Pi * 2a = k * Pi * a/2$$
$$2 = k * 1/2$$
$$k = 4;$$
_________________

If you found my contribution helpful, please click the +1 Kudos button on the left, Thanks

Last edited by Squish on 08 Jun 2012, 01:56, edited 1 time in total.

Kudos [?]: 10 [0], given: 5

Manager
Joined: 15 Apr 2012
Posts: 93

Kudos [?]: 64 [0], given: 134

Concentration: Technology, Entrepreneurship
GMAT 1: 460 Q38 V17
GPA: 3.56
Re: Square A is inscribed in circle X. Square B is inscribed in [#permalink]

### Show Tags

07 Jun 2012, 20:08
Brotha wrote:
Let a = side of square A;
Let b = side of square B;

Perimeter of B = 2b
Perimeter of A = 2a

Perimeter of B = 2 * Perimeter of A
2b = 2 * 2a;
b = 2a;

From Pythagoras rule, length of a diagonal equals \sqrt{2} * side of the square:
Diagonal of square A = $$\sqrt{2} * a$$
Diagonal of square B = $$\sqrt{2} * b = \sqrt{2} * 2a = \sqrt{8} * a$$

Radius of circle X = Half of Diagonal of square A, since square A is inscribed in circle X = $$\sqrt{2} * a/2;$$
Radius of circle Y = Half of Diagonal of square B, since square B is inscribed in circle Y =$$\sqrt{8} * a/2;$$

Area of circle X = $$Pi * r^2 = Pi * (\sqrt{2} * a/2)^2 = Pi * a/2;$$
Area of circle Y = $$Pi * r^2 = Pi * (\sqrt{8} * a/2)^2 = Pi * 2a;$$

Area of circle Y = $$k *$$Area of circle X
$$Pi * 2a = k * Pi * a/2$$
$$2 = k * 1/2$$
$$k = 4;$$

If one side is a then the perimeter should be 4a, right ?Why u wrote 2a?Can you explain?

Kudos [?]: 64 [0], given: 134

Intern
Status: Waiting...
Joined: 10 Jan 2012
Posts: 30

Kudos [?]: 10 [0], given: 5

Concentration: Strategy, International Business
Schools: Duke '15 (M)
GMAT 1: 750 Q48 V42
Re: Square A is inscribed in circle X. Square B is inscribed in [#permalink]

### Show Tags

08 Jun 2012, 01:57
Aaack! Sorry - my mistake! Have updated it - it should be 4a.
_________________

If you found my contribution helpful, please click the +1 Kudos button on the left, Thanks

Kudos [?]: 10 [0], given: 5

Current Student
Joined: 08 Jan 2009
Posts: 323

Kudos [?]: 161 [0], given: 7

GMAT 1: 770 Q50 V46
Re: Square A is inscribed in circle X. Square B is inscribed in [#permalink]

### Show Tags

08 Jun 2012, 05:58
Circle X
let side of square = 1
radius = $$\sqrt{2}$$
area = $$2*(\sqrt{2})^2$$ = $$4$$

Circle y
let side of square = 2
radius = $$\sqrt{8}$$
area = $$2*(\sqrt{8})^2$$ = $$16$$

area of y / area of x = k
16 / 4 = 4

Kudos [?]: 161 [0], given: 7

Manager
Joined: 15 Apr 2012
Posts: 93

Kudos [?]: 64 [0], given: 134

Concentration: Technology, Entrepreneurship
GMAT 1: 460 Q38 V17
GPA: 3.56
Re: Square A is inscribed in circle X. Square B is inscribed in [#permalink]

### Show Tags

08 Jun 2012, 07:23
[quote="pike"]Circle X
let side of square = 1
radius = $$\sqrt{2}$$
area = $$2*(\sqrt{2})^2$$ = $$4$$

Circle y
let side of square = 2
radius = $$\sqrt{8}$$
area = $$2*(\sqrt{8})^2$$ = $$16$$

area of y / area of x = k
16 / 4 = 4[/quote

I want to mention one thing...u said the radius is root 2 for the circle X but actually it's the diagonal of the square not the radius and same for the circle Y..correct me if I am wrong..

Kudos [?]: 64 [0], given: 134

Non-Human User
Joined: 09 Sep 2013
Posts: 15701

Kudos [?]: 281 [0], given: 0

Re: Square A is inscribed in circle X. Square B is inscribed in [#permalink]

### Show Tags

25 Sep 2014, 13:28
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________

Kudos [?]: 281 [0], given: 0

SVP
Status: The Best Or Nothing
Joined: 27 Dec 2012
Posts: 1852

Kudos [?]: 2709 [0], given: 193

Location: India
Concentration: General Management, Technology
WE: Information Technology (Computer Software)
Square A is inscribed in circle X. Square B is inscribed in [#permalink]

### Show Tags

29 Sep 2014, 02:32
pike wrote:

Circle y
let side of square = 2
radius = $$\sqrt{8}$$
area = $$2*(\sqrt{8})^2$$ = $$16$$

area of y / area of x = k
16 / 4 = 4

Though answer is correct, radius / area calculation seems incorrect
_________________

Kindly press "+1 Kudos" to appreciate

Kudos [?]: 2709 [0], given: 193

SVP
Status: The Best Or Nothing
Joined: 27 Dec 2012
Posts: 1852

Kudos [?]: 2709 [0], given: 193

Location: India
Concentration: General Management, Technology
WE: Information Technology (Computer Software)
Re: Square A is inscribed in circle X. Square B is inscribed in [#permalink]

### Show Tags

29 Sep 2014, 02:34
farukqmul wrote:
I want to mention one thing...u said the radius is root 2 for the circle X but actually it's the diagonal of the square not the radius and same for the circle Y..correct me if I am wrong..

As square is inscribed, "Diagonal Of Square" = "Diameter of Circle"
_________________

Kindly press "+1 Kudos" to appreciate

Kudos [?]: 2709 [0], given: 193

Re: Square A is inscribed in circle X. Square B is inscribed in   [#permalink] 29 Sep 2014, 02:34
Display posts from previous: Sort by

# Square A is inscribed in circle X. Square B is inscribed in

 new topic post reply Question banks Downloads My Bookmarks Reviews Important topics

 Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.