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# square root

Author Message
Manager
Joined: 05 Jul 2006
Posts: 195

Kudos [?]: 81 [0], given: 0

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25 Aug 2006, 07:27
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

..

Last edited by lan583 on 11 Feb 2007, 07:51, edited 1 time in total.

Kudos [?]: 81 [0], given: 0

Senior Manager
Joined: 14 Jul 2005
Posts: 398

Kudos [?]: 31 [0], given: 0

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25 Aug 2006, 07:31

lnly sqrt(5) would be greater than 2 and result in a negative square root value.

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Intern
Joined: 22 Aug 2006
Posts: 46

Kudos [?]: [0], given: 0

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25 Aug 2006, 07:38
E for me.

Explanation:

-ve roots are not real.

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Intern
Joined: 12 Aug 2006
Posts: 5

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25 Aug 2006, 07:58
Ans: E.

root of -ve number

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Director
Joined: 28 Dec 2005
Posts: 748

Kudos [?]: 18 [0], given: 0

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26 Aug 2006, 08:38
E, pretty straight

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Current Student
Joined: 29 Jan 2005
Posts: 5201

Kudos [?]: 440 [0], given: 0

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26 Aug 2006, 08:46
Yep, (E) results in a negative square root (i) which is not defined as a real number.

Kudos [?]: 440 [0], given: 0

26 Aug 2006, 08:46
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# square root

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